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marissa [1.9K]
2 years ago
11

Someone please helpppppp

Mathematics
2 answers:
qaws [65]2 years ago
8 0
My opinion is answer 2
Leviafan [203]2 years ago
5 0

Answer:

I think the answer is 2.

Step-by-step explanation:

99-77= 22

22/11= 2

y= 2

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Find the equivalent ratio for 32:__=12:24
Igoryamba
   
32 : 64 = 12 : 24

or


\displaystyle\\
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The number of students in a school increased by 25%between last year and this year. Last year there were 250 students in the sch
alexandr1967 [171]
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Can u solve this for me: 72 + 4x = 2x + 82 and please show work
8_murik_8 [283]
The answer is X = 5 because first you have to take away 2x from that side so u minus 2x from 4x that gives u: 72 + 2x = 82 then you have to minus 72 from both sides and that gives you 2x = 10 once you have that you divide both sides by 2 because you want the X by itself and once you get that X = 5. Hope this helped!
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The distance between two points is 9 and point one is located at (-2, 2), what could be the possible coordinates of point two?
Westkost [7]
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2 years ago
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Let f(x)=x^2f ( x ) = x 2. Find the Riemann sum for ff on the interval [0,2][ 0 , 2 ], using 4 subintervals of equal width and t
sladkih [1.3K]

Answer:

A_L=1.75

Step-by-step explanation:

We are given:

f(x)=x^2

interval = [a,b] = [0,2]

Since n = 4 ⇒ \Delta x = \frac{b-a}{n} = \frac{2-0}{4}=\frac{1}{2}

Riemann sum is area under the function given. And it is asked to find Riemann sum for the left endpoint.

A_L= \sum\limits^{n}_{i=1}\Delta xf(x_i) = \frac{1}{2}(0^2+(\frac{1}{2})^2+1^2+(\frac{3}{2})^2)=\frac{7}{4}=1.75

Note:

If it will be asked to find right endpoint too,

A_R=\sum\limits^{n}_{i=1}\Delta xf(x_i) =\frac{1}{2}((\frac{1}{2})^2+1^2+(\frac{3}{2})^2+2^2)=\frac{15}{4}=3.75

The average of left and right endpoint Riemann sums will give approximate result of the area under f(x)=x^2 and it can be compared with the result of integral of the same function in the interval given.

So, (A_R+A_L)/2 = (1.75+3.75)/2=2.25

\int^2_0x^2dx=x^3/3|^2_0=8/3=2.67

Result are close but not same, since one is approximate and one is exact; however, by increasing sample rates (subintervals), closer result to the exact value can be found.

3 0
3 years ago
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