If we evaluate the function at infinity, we can immediately see that:

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.
We can solve this limit in two ways.
<h3>Way 1:</h3>
By comparison of infinities:
We first expand the binomial squared, so we get

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.
<h3>Way 2</h3>
Dividing numerator and denominator by the term of highest degree:



Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.
But what is the expression, you have to tell me so I can do it.
Answer:
I'm in eight grade so don't assume i'm right. But from looking at this. It looks like x-1=8 and y+1= 28. I'm only doing High School Math 1 in eight grade tho. So if i'm wrong i'm sorry
Step-by-step explanation:
Answer: ∛v
Step-by-step explanation:
Since we know volume is measured height x width x length, we know the equation we'd use here would be:
___ x ___ x ___ = v in³
If this was area, we would have ___ x ___ = v in², and it would be easy to find each blank. You would just find the square root of "v", making your answer √v.
When you have 3 things multiplied by each other (that are exactly the same, which is the situation here since this is a cube), you will want to find ∛x (if x is our unknown variable). This means that we are finding ONE-THIRD of the number ... sort of. So if x was equal to 8, then ∛x = 2, because 2 x 2 x 2 = 8.
In our situation here, x = v, and since we don't know the actual number, we will keep it as a square root, so the answer to your question is ∛v.
I really hope I was able to explain easy enough, feel free to ask anything else!