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svp [43]
3 years ago
13

I need yo help 1+1= i

Mathematics
2 answers:
viva [34]3 years ago
5 0
2

thanks for your time

Have a good day


pav-90 [236]3 years ago
3 0

Answer:

2 my guy

Step-by-step explanation:

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Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3?
OlgaM077 [116]
f(x)=x^2+6x+3

Complete the square:

x^2+6x+a^2\implies a=\dfrac{6x}{2x}=3\implies x^2+6x+3^3

And we have:

f(x)=x^2+6x+3\\\\f(x)=x^2+6x+3^2-3^2+3\\\\f(x)=(x+3)^2-9+3\\\\\boxed{f(x)=(x+3)^2-6}

Answer B.

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3 years ago
I'm a election 4713 people voted candidate B received 2 thirds of the votes. How many votes did candidate b receive
madam [21]

Answer:

3142

Step-by-step explanation:

4713 x 2/3

4 0
4 years ago
Hi can someone plz help me with #1...it’s being graded. sos thanks so much!!
densk [106]
1:105::25:X
105*25whole divided by 1*X
2625
3 0
4 years ago
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What is 2 + 2? I have forgotten the answer to this incredibly complex and difficult question. Only the most brainly and genius o
kakasveta [241]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Luden [163]

Answer:

Both the relations are functions, the correct answer is a.

Step-by-step explanation:

In order to solve this problem we will first find the inverse relation as shown below:

y = 3x^2 + 5\\x = 3y^2 + 5\\3y^2 = x - 5\\y^2 = \frac{x - 5}{3}\\y = \sqrt{\frac{x - 5}{3}} = \frac{\sqrt{x - 5}}{\sqrt{3}}\\y = \frac{\sqrt{x - 5}\sqrt{3}}{\sqrt{3}\sqrt{3}} = \frac{\sqrt{3x - 15}}{3}

Functions are relations between two groups of numbers, for which the input must generate only one output. Using this definition we can classify both the relation and its inverse as a function, therefore the correct answer is a.

7 0
4 years ago
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