A farmer raises cows and chickens. The farmer has a total of 25 animals. One day he counts the legs of all of his animals and co
unts a total of 64 legs.
Let x = number of cows.
Let y = number of chickens.
Which system of equations can be used to solve for the number of cows and the number of chickens on the farm?
1 answer:
Answer:
Step-by-step explanation:
x + y = 25 ...........................(1)
{4x + 2y =64} / 2 divide the equation by 2
2x + y = 32 ........................(3)
Step Two
subtract (1) from (3)
2x + y = 32
x + y = 25
x = 7
Therefore from equation 1 we get x + y = 25
but x = 7
7 + y = 25 Subtract 7 from both sides.
y = 25 - 7
y = 18
Check
4*x + 2*y = 64
4*7 + 2*18 =? 64
28 + 36 = ? 64
64 = 64
The checks out to be the right answer.
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