Question

A farmer raises cows and chickens. The farmer has a total of 25 animals. One day he counts the legs of all of his animals and counts a total of 64 legs.
Let x = number of cows.
Let y = number of chickens.

Which system of equations can be used to solve for the number of cows and the number of chickens on the farm?

Answer 1

Answer:

Step-by-step explanation:

x + y = 25 ...........................(1)

{4x + 2y  =64} / 2    divide the equation by 2

2x + y = 32 ........................(3)

Step Two

subtract (1) from (3)

2x + y = 32

x   + y = 25

x = 7

Therefore from equation 1 we get x + y =  25

but x = 7

7 + y = 25       Subtract 7 from both sides.

y = 25 - 7

y = 18

Check

4*x + 2*y =  64

4*7 + 2*18 =? 64

28 + 36 = ? 64

64 = 64

The checks out to be the right answer.