All categories

3 years ago

The probability of event A is 1/3. The probability of event b is 1/4. What can you include about the two events

Mathematics

1 answer:

Illusion [34]3 years ago

5 0

Answer:

Step-by-step explanation:1/4

You might be interested in

What is the equation of the line that passes through the point (-2, 7) and has a slope of zero

lorasvet [3.4K]

Answer:

y = 7 is the equation of the line that passes through the point ( -2, 7 ) and has a slope of zero.

Step-by-step explanation:

Given:

Let,

A ≡ ( x1 , y1 ) ≡ ( -2, 7 )

Slope = m = 0

To Find :

Equation of Line:

Solution:

Formula for , equation of a line passing through a point ( x1 , y1 ) and having a slope m is given by

$(y - y_{1})=m(x-x_{1})$

Now substituting the values of x1 = -2 and y1 = 7 and slope m = 0 we get,

$y-7=0\times(x--2) \\y-7=0\times (x+2)\\y-7=0\\\therefore y=7$

Which is the required equation of a line passing through the point ( -2, 7 ) and slope zero

6 0

3 years ago

9. The table below shows the change in a stock price over a period of a week. If 12 shares of

ankoles [38]

Answer:

$ 6.24

Step-by-step explanation:

(16.87 - 16.35) x 12 = 6.24

4 0

3 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

Mary scored 10 points less than Judy in the game. Lucy scored twice as many points as

kodGreya [7K]

The answer for this is 10

6 0

3 years ago

Where is the blue point on the number line? 3 ←++ 2. Pls help

My name is Ann [436]

Answer:

its in number 2

please mark as brainliest

6 0

2 years ago

The probability of event A is 1/3. The probability of event b is 1/4. What can you include about the two events​

The probability of event A is 1/3. The probability of event b is 1/4. What can you include about the two events