To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
9514 1404 393
Answer:
17 square units
Step-by-step explanation:
There are several ways you can divide this figure into areas that are easily computed.
One that comes to mind is to consider the triangle that would include the missing area at lower right. That triangle would have a base of 6 and a height of 8, so an area of ...
A = (1/2)bh
A = (1/2)(6)(8) = 24 . . . . square units
The part at lower right that is cut out is a sort of reversed L-shape that is 3 squares along the bottom and 4 more up the side, for a total of 7 squares.
Then the area of the shaded part is ...
A = 24 - 7 = 17 . . . . square units
Answer:
16%
Step-by-step explanation:
406 / 350 = 1.16
406 is 116% of 350
so 350 + 16% is 406
because 350 * 0.16 = 56
56 is 16%
350 + 56 = 406
:)
Answer:
When you distribute the 7 to each set you get 14-21n and 14-21n
Step-by-step explanation:
