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pochemuha
3 years ago
12

What is the equation of the graph below?

Mathematics
1 answer:
kolezko [41]3 years ago
6 0
Answer is D. No negative in front because the parabola opens upwards. x+3 moves it left 3. And - 1 moves it down one
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PLEASE ANSWER ASAP WILL GIVE BRAINLEIST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Step2247 [10]

Answer:

r = 16

Step-by-step explanation:

Cross multiply:

4 x 20 = r x 5

Simplifying

4 x 20 = r x 5

Multiply 4 x 20

80 = r x 5

Reorder the terms for easier multiplication:

80 = 5r

Solve

80 = 5r

Solve for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-5r' to each side of the equation.

80 + -5r = 5r + -5r

Combine like terms: 5r + -5r = 0

80 + -5r = 0

Add '-80' to each side of the equation.

80 + -80 + -5r = 0 + -80

Combine like terms: 80 + -80 = 0

0 + -5r = 0 + -80

-5r = 0 + -80

Combine like terms: 0 + -80 = -80

-5r = -80

Divide each side by '-5'.

r = 16

Simplify

r = 16

5 0
3 years ago
sandy had 10 dollars in her collection. she gave 3 to her younger sister. her parents were so impressed that they quadrupled her
pantera1 [17]
(10-3)*4

Hope this helps!
7 0
3 years ago
Read 2 more answers
6 points
kodGreya [7K]

Answer:

y=-2\,(x+3)^2-3

Step-by-step explanation:

Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex (x_v,y_v) in the expression:

y-y_v=a\,(x-x_v)^2\\y=a\,(x-x_v)^2+y_v

we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter a:

y=a\,(x-x_v)^2+y_v\\y=a\,(x+3)^2+(-3)\\y=a\,(x+3)^2-3\\-5=a\,(-2+3)^2-3\\-5=a\,(1)-3\\a=-5+3\\a=-2

So, now we can write the full expression for the parabola:

y=a\,(x+3)^2-3\\y=-2\,(x+3)^2-3

8 0
3 years ago
Select the correct inequality sign to make the statements true.
My name is Ann [436]

Answer:

< then >

Step-by-step explanation:

11 7/8 can be written as (11 + 7/8). If we find (11+7/8)², we know that √(11+7/8)² = (11+7/8), so we can compare (11+7/8)² with 129 and see which is bigger.

(11+7/8)² = (11+7/8) * (11+7/8)

= 121 + 7/8 * 11 + 7/8 * 11 + (7/8)²

= 121 + 77/8 + 77/8 + (7/8)²

77/8 is greater than 9 (8*9 = 72) but less than 10 (8*10=80). Rounding down to 7, we have

121 + 7 + 7 + (7/8)²

= 135 + (7/8)²

Even when rounding down, (11+7/8)² is greater than 129. Therefore,

129 < (11+7/8)²

square root both sides

√129 < (11+7/8)

We can apply a similar process for the next one.

(3+5/6)² = (3+5/6) * (3+5/6)

= 9 + 5/6 * 3 + 5/6 * 3 + (5/6)²

= 9 + 15/6 + 15/6 + (5/6)²

15/6 is less than 3 (6*3 = 18) but greater than 2 (6*2 = 12). Rounding down to 2, we have

9 + 2 + 2 + (5/6)²

= 13 + (5/6)² > 10

Even when rounding down, (3+5/6)² is greater than 10

(3+5/6)² > 10

square root both sides

(3+5/6) > √10

8 0
3 years ago
36=u/5+13 <br><br> Equations
liq [111]
\frac{u}{5}+13=36 ⇒ \frac{u}{5}=36-13 = 23

u=23*5

\boxed {u=115}
8 0
3 years ago
Read 2 more answers
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