Question

Determine the temperature of 2.6 moles of gas contained in a 5.00-L vessel at a pressure of 1.2atm.

Answer 1

Answer:

28.108 K.

Step-by-step explanation:

Given: Pressure (P)= 1.2atm

           Number of moles (n)=  2.6 moles

           Volume (V)= 5.00-L

Now finding the temperature (T).

Formula; T= $\frac{P\times V}{n\times R}$

R is a constant factor which makes other factors work together.

There is a numerical value for R which we use is $0.0821 \times \frac{L.atm}{mole.K}$

∴ Temperature (T)= $\frac{1.2\times 5}{2.6\times 0.0821 \frac{L.atm}{mol.K} }$

⇒ Temperature (T)= $\frac{6}{0.21346} = 28.1083\ K$

∴ Temperature is 28.108 K