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2 years ago

What is 3 x 89 - 394 +35.32 x 34/289 x 100,000,000 - 3832 / 24213

Mathematics

2 answers:

Whitepunk [10]2 years ago

3 0

415529284.606 is the correct answer

CaHeK987 [17]2 years ago

3 0

Answer:

415529284.6

Step-by-step explanation:

Use BODMAS to help you work this out

This stands for Brackets Orders Divisions Multiplications Additions Subtraction
It tells you what to do first, go from left to right, so

Brackets, do we have any? No so next step
Orders, this means exponents in simplest terms, do we have exponents? No, so next
Divisions, do we have anything to divide? Yes, divide -3832 by +24213 <em>always use the number with the sign</em>. So $-3822\div24213=-\frac{3822}{24213}$ since we can't simplify it, leave it as a fraction
Multiplications, do we have any? Yes, $3\times 89$ and $+35.32\times \frac{34}{289} \times100,000,000$ . So we work them out $3\times89=267$ and $+35.32\times \frac{34}{289} \times100,000,000=\frac{120,088,000,000}{289}$ . Then let's write down everything with out new answers $267-394+\frac{120,088,000,000}{289}-\frac{3822}{24213}$
Additions, do we have any? Yes, one and that's $-394+\frac{120,088,000,000}{289}$ this equals $+\frac{7063993302}{17}$ so our new term is $267+\frac{7063993302}{17}-\frac{3822}{24213}$ but there's more adding to be done $267+\frac{7063993302}{17}=\frac{7063997841}{17}$ So now we have $\frac{7063997841}{17}-\frac{3832}{24213}$
Subtractions, we do the last bit $\frac{7063997841}{17}-\frac{3832}{24213}=415529284.6$

That's how you do that lol

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2 years ago

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2 years ago

Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).

Serjik [45]

Answer:

$\displaystyle f(x)=x^2+2x+2$

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

$\displaystyle f(x)=ax^2+bx+c$

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

$\displaystyle f(-1)=a(-1)^2+b(-1)+c$

$\displaystyle f(-1)=a-b+c$

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Now we use the second condition f(1)=5

$\displaystyle f(1)=a(1)^2+b(1)+c$

$\displaystyle f(1)=a+b+c$

$\displaystyle a+b+c=5.......[eq\ 2]$

Finally, we use the third condition f(2)=10

$\displaystyle f(2)=a(2)^2+b(2)+c$

$\displaystyle f(2)=4a+2b+c$

$\displaystyle 4a+2b+c=10....[eq\ 3]$

We put together eq 1, eq 2, and eq 3 to form the system

$\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.$

Adding the first two equations we have

$\displaystyle 2a+2c=6$

$\displaystyle a+c=3$

And also

$\displaystyle b=2$

Using the above equation and the value of b in the third equation, we have

$\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.$

Subtracting the first equation from the second

$\displaystyle 3a=3$

$\displaystyle a=1$

And therefore

$\displaystyle c=2$

Now we have all the values, the quadratic function is

$\displaystyle \boxed{f(x)=x^2+2x+2}$

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2 years ago

One speed skater starts across a frozen lake at an average speed of 8 m/s. Ten seconds later, a second speed skater starts from

Galina-37 [17]

Answer: Hello mate!

Let's define the variable t as the time, and define t = 0 as the moment when the first skater starts to move:

We know that the speed of the first skater is 8 m/s, and we need to find the position as a function of time, then we need to integrate the velocity over time

if v1(t) = 8m/s

then p1(t) = (8m/s)*t

now we also know that the second skater has a velocity of 9m/s and enters in the frozen lake at t= 10s.

then the velocity of the second skater is: v2(t) = 9m/s, and the position is:

p2(t) = (9m/s)*(t - 10s)

now we want to know how many seconds after the second skater starts are needed for the second skater to overtake the first one.

this is equivalent to see when his positions will be equal.

so p1(t) = p2(t):

(8m/s)*t = (9m/s)(t - 10s) = (9m/s)*t - 90m

(8m/s)*t - (9m/s)*t = -90m

(-1m/s)*t = 90m

t = 90m/(1m/s) = 90s

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