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4 years ago

Solve for x. 2x + 2 = -8 X=???? Please help!?

Mathematics

2 answers:

Fiesta28 [93]4 years ago

7 0

Answer:

x=-5

Step-by-step explanation:

1.) 2x+2=-8 start to isolate the variable by subtracting 2 to -8

2.) 2x=-10 divide both sides by 2

3.) x=-5

Hope this helped

tino4ka555 [31]4 years ago

3 0

Answer:

x = - 5

Step-by-step explanation:

2x + 2 = - 8

2x = - 8 - 2

2x = - 10

x = - 10 : 2

x = - 5

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Y = 6x; (2,12) tell weather the ordered pair is a solution of the equation

svet-max [94.6K]

Hi!

I can help you with joy!

Plug in the values and solve:
Instead of y, plug in 12 (the y-coordinate)
Instead of x, plug in 2 (the x-coordinate)
Then, if we end up with a true statement, then the ordered pair is a solution of the equation.
12=6(2)
12=12
Yeah! It worked! :)

Answer:

Yes, (2,12) is a solution of the equation y=6x.

Hope it helps.

Do comment if you have any queries regarding my answer.

~Misty~

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3 years ago

Erik rides his motorbike 26 2/3 miles in 2/3 hour. What is Erik’s average speed in miles per hour? Enter the number in the box.

Scilla [17]

Answer:

40 mph

Step-by-step explanation:

average speed 40mph

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3 years ago

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Pls kindly help, it's urgent

nordsb [41]

Answer: 6400

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3 years ago

A student determined that the area of the segment of c shown above is Asegment = 137.71 ft2. The student's work is shown below.

ivolga24 [154]

Answer:

Option D. The student did not use the correct formula to calculate the area of the segment

Step-by-step explanation:

step 1

Find the area of the isosceles triangle

Applying the law of sines

$A=\frac{1}{2}(12^{2})sin(60\°)=62.35\ ft^{2}$

step 2

Find the area of the sector

The area of the sector is 1/6 of the area of the circle

$A=\pi r^{2}/6$

substitute the value

$A=(3.14)(12)^{2}/6=75.36\ ft^{2}$

step 3

Find the area of the segment

The area of the segment is equal to the area of sector minus the area of triangle

$A=75.36\ ft^{2}-62.35\ ft^{2}=13.01\ ft^{2}$

therefore

The student did not use the correct formula to calculate the area of the segment

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3 years ago

Nadia compares the weights, in grams, of some apples and oranges. She finds the median and interquartile range of the weights. M

Leto [7]

Answer:

The higher the interquartile range the bigger the variance as it the difference between the 0.25 and 0.75 quantiles. which basically means if the difference between the 25 percent and 75 percent is higher then there is more variety as they are further away.

Step-by-step explanation:

Which basically means if the difference between the 25 percent and 75 percent is higher then there is more variety as they are further away.

Would be amazing if you marked brainliest and feel free to comment any follow up questions ^^

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3 years ago

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