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Yuki888 [10]
4 years ago
15

What is cos 30°? 60 2 30 90*

Mathematics
2 answers:
REY [17]4 years ago
7 0
It’s 90 or 60 I believe
Eduardwww [97]4 years ago
6 0
90 i think maybe 60.
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Determine the best answer
kicyunya [14]
Let’s assume the point in the centre is the origin of the circle.

This means the radius is 21/2 = 10.5cm.

180 - 168 = 12 degrees as the angle between BC.

Circumference of a sector is:

Angle/360 • pi • diameter

=12/360 • pi • 21 cm

= 2.19 cm = 2.20 cm

Which is option B
7 0
3 years ago
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A small company’s net income for the first six months of the year was $76,500 and for the last six months it was $100,000. What
kkurt [141]
Hello

Answer: The ratio of the first 6 months to the last 6 months is 0.765.
First, we need to determine the amount of money they had in each 6 month period.
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Have a nice day
8 0
3 years ago
Compute the correlation coefficient for the data set. (2,19), (3,22), (4,26), (5,20), (6,35), (7,30), (9,40), (10,42), (11,35)
lakkis [162]

Answer:

The correlation coefficient  of the data is 0.8679.

Step-by-step explanation:

The formula to compute the correlation coefficient is:

r(X,Y)=\frac{n\cdot \sum XY-\sum X\cdot \sum Y}{\sqrt{n\cdot\sum X^{2}-(\sum X)^{2}}\times \sqrt{n\cdot\sum Y^{2}-(\sum Y)^{2}}}

From the data provided compute the values of ∑ XY, ∑ X, ∑ Y, ∑ X² and ∑ Y².

The values are computed in the table below.

Compute the correlation coefficient as follows:

r(X,Y)=\frac{n\cdot \sum XY-\sum X\cdot \sum Y}{\sqrt{n\cdot\sum X^{2}-(\sum X)^{2}}\times \sqrt{n\cdot\sum Y^{2}-(\sum Y)^{2}}}

            =\frac{(9\times 1893)-(57\times 269)}{\sqrt{(9\times 441)-(57)^{2}}\times \sqrt{(9\times 8635)-(269)^{2}}}\\\\=\frac{1704}{\sqrt{720\times 5354}}\\\\=0.86788895\\\\\approx 0.8679

Thus, the correlation coefficient  of the data is 0.8679.

4 0
3 years ago
Two cars start together in the same direction from the same place. The first goes with a uniform speed of 10 km/h. The second go
Inga [223]

Let the second car meets the first car after n hours.

Second car starts with 8km/h, After succeeding hours his speed increases by 0.5 km.

So, Distance travelled by second car = 8 + 8.5 + 9

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eqn. (1) sum of n terms Of A.P with first term 8

and common difference 0.5.

Sum of all the terms in equation 1 is also equals to the distance travelled by the first car for n hours, i.e. 10n km .

Now, we have (n/2) {16+(n-1) 0.5} = 10n........(2)

From equation (2) we get, n= 9

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Hope it helps!

7 0
3 years ago
It takes Jimmy 11 minutes to sweep a porch.
lara31 [8.8K]
Like 6 minutes or somthin
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4 years ago
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