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qwelly [4]
3 years ago
14

How to solve 55+66(distributive property)

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0
55 + 66 = [11×5] + [11×6]

11 is the common factor of 55 and 66
Taking 11 out gives 11×(5+6)
Working out  11×11 = 121
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Write a set of steps to describe how to use the elimination method with the system of equations.
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4 years ago
For each of the numbers a, b, c, d, r, and s, state whether the function whose graph is shown has an absolute maximum or minimum
lutik1710 [3]

enter the following:

s

a;r

b

c

d

if you got question on how to determine these, just ask :)

5 0
3 years ago
What value of m makes this equation true?
iris [78.8K]
The correct answer is B) m=-8

First, add 9 on both sides of the equation. You should end up with 4m=-32.

Next, divide both sides of the equation by 4. You should end up with m=-8. (A negative divided by a positive equals a negative)

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6 0
3 years ago
Five bulbs of which three are defective are to be tried in two bulb points in a dark room
iogann1982 [59]

Answer:

D 7

Step-by-step explanation:

Total no. of bulb= 5

no. of defected bulb= 3

no. of not defected bulb=2

Total no. of bulb combination = 5C2

=5!/2!(5-2)!

= 5!/2!3!

= 5×4×3×2×1/2×1×3×2×1

=120/12

=10

( since a room can be lighted with one bulb also)

total no. of bulb combination when room shall not light = 3C2

3!/2!(3-2)!

= 3!/2! 1!

= 3×2×1/2×1×1

= 6/2

=3

Now,

Total no. of trial when room shall light

=10-3

=7

Hence, number of trial when the room shall be lighted is 7 which is option d

8 0
3 years ago
Factorize<br>please <br>help<br>me <br><br><img src="https://tex.z-dn.net/?f=a%20%7B%7D%5E%7B2%7D%20%20-%204b%20%7B%7D%5E%7B4%7D
Vsevolod [243]

Answer:

(a+2b^{2} )(a-2b^2)

Step-by-step explanation:

You have what is called "perfect squares" so you can use the "difference of squares formula to factor:

a^2-b^2=(a+b)(a-b)

So,

a^2-(2b^2)^2

you can work the equation backward now and you will get your original equation.

8 0
3 years ago
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