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qwelly [4]
3 years ago
14

How to solve 55+66(distributive property)

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0
55 + 66 = [11×5] + [11×6]

11 is the common factor of 55 and 66
Taking 11 out gives 11×(5+6)
Working out  11×11 = 121
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Gregory has agreed to donate $100 to Spring Valley High School for its library. In addition, he will donate $15 for every book a
sladkih [1.3K]

Answer:

a_n=15n+100 where n =1, 2, 3, .....

Step-by-step explanation:

Given that:

Amount of money to be donated by Gregory = $100

Amount of money to be donated for every book that a student will read = $15

The series becomes:

100, 115, 130, 145, 160, .....

To find:

The explicit formula to represent this problem situation.

Solution:

First of all, let us have a look at the difference of each term from its previous term.

Second term - First term = 115 - 100 = 15

Third term - Second term = 130 - 115  = 15

Fourth term - Third term = 145 - 130 = 15

The difference is same, therefore the given series is an Arithmetic Progression (AP).

We have to find the n^{th} term of the given AP.

Formula for n^{th} term:

a_n=a+(n-1)d

a is the first term and

d is the common difference.

Here, a = 115 (because $100 is the fixed amount so first term is taken as 115 when one book is read)

d = 15

Putting the values, we get:

a_n=115+(n-1)15\\\Rightarrow a_n=115+15n-15\\\Rightarrow a_n=15n+100

Therefore, formula to represent the situation is:

a_n=15n+100 where n =1, 2, 3, .....

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X+y=2 và x-y=4 tim x và y
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Step-by-step explanation:

X

xx - xxyy  - yy = 8

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