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Alenkinab [10]
3 years ago
12

A geometric sequence is represented by a Subscript n Baseline = a Subscript 1 Baseline r Superscript n minus 1. What is the fift

h term of a geometric sequence where a Subscript 1 Baseline = 4,096 and the common ratio is Negative one-fourth?
Mathematics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

<h2>16</h2>

Step-by-step explanation:

Given the nth term of a geometric sequence represented as Tn = a_1r^{n-1}

a_1 =  first term of the sequence

n = number of terms

r = common ratio

Given a_1 = 4,096,\ r = -\frac{1}{4} , n = 5(fifth term of the sequence)

T_5 = 4,096(-\frac{1}{4} )^{5-1}\\ T_5 = 4,096(-\frac{1}{4} )^{4}\\T_5 = 4,096(\frac{1}{256} )\\T_5 = 16

The fifth term of the geometric sequence is 16

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