What is 6x-3y=9 I can't figure it out
1 answer:
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Answer:
Standard equation of a circle
(x−3+(y−3
=4
General form of the equation of a circle
−6x+
−6y+14=0
Parametric equations of a circle
x=2cosθ+3
y=2sinθ+3
Answer:
C'(4,4)
Step-by-step explanation:
The dilation of quadrilateral ABCD over the origin by a scale factor of 2 has the rule
(x,y)→(2x,2y)
So,
- A(-3,-1)→A'(-6,-2)
- B(-1,1)→B'(-2,2)
- C(2,2)→C'(4,4)
- D(3,-2)→D'(6,-4)
Hence, the coordinates of the image point C' are (4,4) (see attached diagram for details)
