Hope my answer helps you! :D
The answer to your question is c.
Answer:
a)
b)
c)
But we see that the distribution is defined ust between 49.62 and 50.04
And in order to find this we can use the CDF (Cumulative distribution function) given by:

And if we replace we got:

And makes sense since all the values are between 49.62 and 50.04
Step-by-step explanation:
For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:

Part a
For the uniform distribution the expected value is given by
where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:
Part b
The variance for an uniform distribution is given by:
And if we replace we got:
Part c
For this case we want to find this probability:
But we see that the distribution is defined ust between 49.62 and 50.04
And in order to find this we can use the CDF (Cumulative distribution function) given by:

And if we replace we got:

And makes sense since all the values are between 49.62 and 50.04
Super easy all you do is grab 3500*0.7306 which equals 2557.1 2557.1 is correct hope this helps
There are 6 less boys then girls
there are 6 more girls then boys
there are 15 boys compared to 21 girls