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3 years ago

Solve 64^x = 16^(x−1). (1 point) Select one: a. x = −2 b. x = −1 c. x = negative 1 over 4 d. x = negative 1 over 3

Mathematics

2 answers:

Ainat [17]3 years ago

8 0

Answer:

$\huge \boxed{x=-2}$

Step-by-step explanation:

64^x = 16^(x-1)

Rewrite the bases with base of 4.

(4^3)^x = (4^2)^(x-1)

Multiply exponents.

4^(3x) = 4^(2(x-1))

Cancel same bases.

3x = 2(x-1)

Expand brackets.

3x = 2x - 2

Subtract 2x from both sides.

x = -2

LekaFEV [45]3 years ago

6 0

Answer:

a. x = -2

Step-by-step explanation:

64ˣ = 16⁽ˣ⁻¹)

64 = 4³

16 = 4²

4³⁽ˣ⁾ = 4²⁽ˣ⁻¹)

4³ˣ = 4²ˣ⁻²

3x = 2x - 2

x = -2

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Y = 3x + 15<br> 3x + 3y = 9

Zina [86]

Answer:

$\Large\boxed{x=-3}$ $\Large\boxed{y=6}$

Step-by-step explanation:

<u>Given the system of equations</u>

$1)~y=3x+15$

$2)~3x+3y=9$

<u>Divide 3 on both sides of the 2) equation</u>

$3x+3y=9$

$3x\div3+3y\div3=9\div3$

$x+y=3$

<u>Current system</u>

$1)~y=3x+15$

$2)~x+y=3$

<u>Substitute 1) equation into the 2) equation</u>

$x+(3x+15)=3$

<u>Combine like terms</u>

$x+3x+15=3$

$4x+15=3$

<u>Subtract 15 on both sides</u>

$4x+15-15=3-15$

$4x=-12$

<u>Divide 4 on both sides</u>

$4x\div4=-12\div4$

$\Large\boxed{x=-3}$

<u>Substitute the x value into one of the equations to find the y value</u>

$y=3x+15$

$y=3(-3)+15$

$y=-9+15$

$\Large\boxed{y=6}$

Hope this helps!! :)

Please let me know if you have any questions

4 0

1 year ago

What’s the value of the blue dot

bixtya [17]

Answer:

-22

Step-by-step explanation:

Each line is worth 3 units

-10 - (-16) = 6 units between and there are 2 spaces

6/2 = 3

We are going down so it is negative

-16 -3 =-19

then the dot is on the next line

-19 -3 = -22

7 0

3 years ago

The following system has a solution: x=10, y=-3, z=14

wolverine [178]

<h2>Answer:</h2><h3>False</h3>

<h2>Step-by-step explanation:</h2>

In this problem, we have the following System of Three Equations in Three Variables, so our goal is to determine whether $x=10, \ y=-3, \ z=14$ is the solution to this system, that is, the ordered triple $P(x,y,z)$ where three planes intersect.

The easier way to find the answer is to plug in the x, y and z values in the equations and figure out whether the equations satisfy the solutions. Then:

$First \ Equation: \\ \\ 3(10)+7(-3)-14=-5 \\ \\ It \ satisfies \ the \ first \ equation \\ \\ \\ Second \ Equation: \\ \\ 9(10)-(-3)-4(14)=37 \neq 17 \\ \\ It \ doesn't \ satisfy \ the \ second \ equation$