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Marat540 [252]
3 years ago
12

A function, h(x), is defined as shown.

Mathematics
2 answers:
Juliette [100K]3 years ago
7 0
The second one! The others do not follow the piecewise function stated.
Fed [463]3 years ago
3 0

Answer:

option B

Step-by-step explanation:

We have three different function for h(x)

h(x)= \frac{1}{4}x-4, x

WE have x<=0, so the graph starts at x=0 and goes down

Plug in 0 for x

h(0)= \frac{1}{4}(0)-4

So h(0)= -4

When x=0, y= -4

The graph starts at (0,-4) and goes down

h(x)= \frac{1}{3}x-3, 0

x lies between 0  and 3, so the graph starts at x=0 and ends at x=3

Plug in 0 for x

h(0)= \frac{1}{3}(0)-3

So h(0)= -3

When x=0, y= -4

Plug in 3 for x

h(3)= \frac{1}{3}(3)-3=-2

When x=3, y= -2

The graph starts at (0,-4) and ends at (3, -2)

h(x)= \frac{1}{2}x-2, x>=4

WE have x>=4, so the graph starts at x=4 and goes to the right

Plug in 4 for x

h(4)= \frac{1}{2}(4)-2

So h(4)= 0

When x=4, y= 0

The graph starts at (4,0) and goes to the right.

SEcond graph is correct


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According to the Mortgage Bankers Association, 8% of U.S. mortgages were delinquent in 2011. A delinquent mortgage is one that h
shepuryov [24]

Answer:

The probability that exactly one of these mortgages is delinquent is 0.357.

Step-by-step explanation:

We are given that according to the Mortgage Bankers Association, 8% of U.S. mortgages were delinquent in 2011. A delinquent mortgage is one that has missed at least one payment but has not yet gone to foreclosure.

A random sample of eight mortgages was selected.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 8 mortgages

            r = number of success = exactly one

           p = probability of success which in our question is % of U.S.

                  mortgages those were delinquent in 2011, i.e; 8%

<em>LET X = Number of U.S. mortgages those were delinquent in 2011</em>

So, it means X ~ Binom(n=8, p=0.08)

Now, Probability that exactly one of these mortgages is delinquent is given by = P(X = 1)

                 P(X = 1)  = \binom{8}{1}\times 0.08^{1} \times (1-0.08)^{8-1}

                               = 8 \times 0.08 \times 0.92^{7}

                               = 0.357

<u><em>Hence, the probability that exactly one of these mortgages is delinquent is 0.357.</em></u>

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3 years ago
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Step-by-step explanation:

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