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mote1985 [20]
3 years ago
12

Multiply -3x^2(6x^2+2x-3)

Mathematics
2 answers:
Cloud [144]3 years ago
8 0

Answer:

-18x^{4} - 6x^{3} + 9x^{2}

Step-by-step explanation:

Multiply each term in the parentheses by -3x^{2}

-3x^{2} × 6x^{2}  - 3x^{2} × 2x - 3x^{2} × (-3)

Calculate the products:

-18x^{4} - 6x^{3} - 9x^{2}

AveGali [126]3 years ago
4 0

Answer:

342x²-27x

Step-by-step explanation:

-3x^2(6x^2+2x-3)

9x(36x+2x-3)

324x²+18x²-27x

342x²-27x

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What is 7.985 add 12.84 show your work
nataly862011 [7]

Answer:

20.825

Step-by-step explanation:

 7.985

+12.84

 20.825

8 0
3 years ago
Read 2 more answers
HELP ASAP!!!!!!!PLEASE SHOW WORK!!!!!! !!!!!
DENIUS [597]

Answer:

Area = 12.82 miles²

Step-by-step explanation:

Area of a triangle with two adjacent sides and the inscribed angle between these side is given by,

Area = \frac{1}{2}ab[\text{sin(C)}]

By substituting the values of sides a, b and the angle C,

Area = \frac{1}{2}(5.7\times 9.3)[\text{sin}(14^{\circ})]

        = 12.82 square miles

4 0
3 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca
Alecsey [184]

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

4 0
4 years ago
Simplify the radical <br> Sqrt 84x^7
pentagon [3]

Answer:

\large\boxed{\sqrt{84x^7}=2x^3\sqrt{21x}}

Step-by-step explanation:

Domain:\ x\geq0\\\\\sqrt{84x^7}=\sqrt{4\cdot21\cdot x^{6+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot21\cdot x^6\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{21}\cdot\sqrt{x^{3\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{21}\cdot\sqrt{(x^3)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{21}\cdot x^3\cdot\sqrt{x}=2x^3\sqrt{21x}

6 0
3 years ago
Graph the line that contains the point (-2,7) and has slope of 4
allsm [11]
Go up 7 on the coordinate plane (up 7 on the y-axis). Go left 2 on the x-axis. Draw a dot where -2 and 7 meet. That is the point. Assuming you have a grid go up 4 and 1 to the right. Draw a point. Then go back to the first point (-2,7). Go down 4 and 1 to the left. Repeat this as many times as you want. Connect the points and draw the line.
6 0
3 years ago
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