Answer:
Length: About 7.61 millimeters
Step-by-step explanation:
Let's first calculate the circumference of Circle W. Now given that the radius WS is 4.5 millimeters, apply the circumference formula as such to get the circumference:
Circumference = 2πr = 2π * (4.5) = 2 * (4.5)π = 9π
The circumference will come in handy later, so now let us calculate the degree measure of arc TS. We can see that TQ and PR act as diameters. From this we conclude that:
mPT + mPQ = 180,
mPT = mQR (Vertical, thus congruent),
mQR + mRS + mTS = 180
Let's substitute known values into the first equation:
mPT + mPQ = 180,
mPT + 128 = 180,
mPT = 52 degrees
This means that:
mQR = 52 degrees
Now let's substitute known values into the third equation:
mQR + mRS + mTS = 180,
52 + 31 + mTS = 180,
83 + mTS = 180,
mTS = 97 degrees
Knowing the degree measure of the arc we need to calculate, we can apply a proportionality including the circumference as such:
mTS / 360 = TS / Circumference
Let's substitute known values into the equation and solve for TS:
97 / 360 = TS / 9π,
97 (9π) = 360 (TS) (Cross multiplication),
873π = 360 (TS),
TS = 873π / 360
TS = 2.425π
TS = 2.425 (3.14159265.....)
TS = About 7.62 or 7.61 (depends on length of π)
Answer:
4
Step-by-step explanation:
4-0.25g +0.5h
We have,
g=10
h=5
Putting the values,
4-0.25g +0.5h= 4-0.25*10+0.5*5 =4 -2.5 +2.5 = 4
Answer:
x=6
Step-by-step explanation:
By the Product Rule of Logarithms, the logarithm of the product of numbers is the sum of the logarithms of the numbers.
Raise both sides to the power of 10 to eliminate the logs, obtaining:
x = -2 or x = 6. Since x = -2 is extraneous, it follows that x = 6.
Answer:
£32 and £32
Step-by-step explanation:
The computation of the amount that should be left and equally distributed is shown below:
The cost of hotel for one night is £84
Brenda has make a deposit of £20
So, the remaining amount left is
= £84 - £20
= £64
Now this amount should be equally distributed between them i.e. £32 and £32
Answer:
3/4
Step-by-step explanation:
divided by 3 to get the answer.