Answer:
x=23,y=15
Step-by-step explanation:
take away 8 from 38, divide it by 2, you get 15. add 8 to one of the set of two 15s. you get 23 and 15
There is no picture of the graph
I will assume that you meant:
(x+4)/(-3x^2+12x+36) factor the denominator...
(x+4)/(-3(x^2-4x-12))
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=-12 and j+k=b=-4 so j and k must be 2 and -6 and the factors are then:
(x+2)(x-6) so we are now left with:
(x+4)/(-3(x+2)(x-6))
The only restriction on this function is that division by zero is undefined, so x cannot equal -2 or 6
Answer:
<h2>
y = ²/₅
x - 3</h2>
Step-by-step explanation:
Changing to slope-intercept form:
5x + 2y = 12 {subtract 5x from both sides}
2y = -5x + 12 {divide both sides by 2}
y = -⁵/₂
x + 6
y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1
{Two lines are perpendicular if the product of theirs slopes is equal -1}
y =-⁵/₂
x + 1 ⇒ m₁ = -⁵/₂
-⁵/₂×
m₂ = -1 ⇒ m₂ = ²/₅
So, any line perpendicular to 5x + 2y = 12 must have slope m =²/₅
