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3 years ago

Does anyone know ? I will really appreciate it

Mathematics

2 answers:

Ghella [55]3 years ago

5 0

Answer:

I'm pretty sure that's neither

Step-by-step explanation:

parallel would be side by side and perpendicular would be intersecting

kakasveta [241]3 years ago

3 0

:

I’m pretty sure it neither

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Answer:

D. 180

good luck, i hope this helps :)

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3 years ago

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Which type(s) of symmetry does the following object have?

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The mass of earth 6*10^24kg and radius is 400kg Now find the value of acceleration due to gravity when a object is 3600km from the earth surface

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2 years ago

I can't seem to figure this one out. Could someone show how to do it and the answer? Thanks in advance!

vagabundo [1.1K]

Answer:

$\displaystyle (-\infty, -\frac{1}{6})$

Step-by-Step explanation:

We have the function:

$\displaystyle y=\int_{1}^{x}\frac{1}{3+t+3t^2}\, dt$

And we want to find the interval for which y is concave upwards.

Therefore, we will need to find the second derivative of y, find its inflection points (where y''=0), and test for values.

So, let's take the derivative of both sides with respect to x. So:

$\displaystyle y^\prime=\frac{d}{dx}\Bigg[\int_{1}^{x}\frac{1}{3+t+3t^2}\, dt\Bigg]$

By the Fundamental Theorem of Calculus:

$\displaystyle y^\prime=\frac{1}{3+x+3x^2}$

So, we will take the derivative again. Hence:

$\displaystyle y^\prime^\prime=\frac{d}{dx}\Big[\frac{1}{3+x+3x^2}\Big]=\frac{d}{dx}\Big[(3+x+3x^2)^{-1}\Big]$

We will use the chain rule. Let:

$\displaystyle u=x^{-1}\text{ and } v=3+x+3x^2$

Differentiate:

$\displaystyle y^\prime^\prime=-(3+x+3x^2)^{-2}(1+6x)$

Rewrite:

$\displaystyle y^\prime^\prime=-\frac{6x+1}{(3+x+3x^2)^2}$

So, points of inflection, where the concavity changes, is whenever the second derivative is 0 or undefined.

We can see that the second derivative will never be undefined since the denominator can never equal 0.

So, our only possible inflection points are when it's equal to 0. Hence:

$\displaystyle 0=-\frac{6x+1}{(3+x+3x^2)^2}$

Multiplying both sides by the denominator gives:

$0=-(6x+1)$

Then it follows that:

$\displaystyle x=-\frac{1}{6}$

So, our only possible point of inflection is at x=-1/6.

We will test for values less than and greater than this inflection point.

Testing for x=-1, we see that:

$\displaystyle y^\prime^\prime=-\frac{6(-1)+1}{3+(-1)+3(-1)^2}=1>0$

Since the result is positive, y is concave up for all values less than -1/6.

And testing for x=0, we see that:

$\displaystyle y^\prime^\prime=-\frac{6(0)+1}{3+(0)+3(0)^2}=-\frac{1}{3}$

Since the result is negative, y is concave down for all values greater than -1/6.

Therefore, the interval for which y is concave up is:

$\displaystyle (-\infty, -\frac{1}{6})$

Note that we use parentheses instead of brackets since at exactly x=-1/6, our graph is neither concave up nor concave down.

5 0

3 years ago

draw to show the numbers. write the numbers to solve. Charlie gathers Poles, pears ,and plums. the numbers of apples and plums a

Savatey [412]

2 x 10 = 20 apples and plums that Charlie should gather :)

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3 years ago

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The Quotient of x and 5 is greater than 22

-Dominant- [34]

Answer:

$\frac{x}{5}$ > 22

x = > 110

Step-by-step explanation:

This is the answer because:

1) The quotient of x and 5 means the answer to a division problem. Therefore, it's $\frac{x}{5}$

2) Greater than 22 means the quotient has to be anything greater than 22. Therefore it is > 22

3) Finally, x is equal to anything greater than 110 because 22 x 5 is 110. Therefore, x has to equal anything greater than 110

The final answer is:

$\frac{x}{5}$ > 22

x = > 110

Hope this helps!

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3 years ago