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3 years ago

Simplify this problem

Mathematics

2 answers:

madam [21]3 years ago

5 0

Answer:

there is no problem

Step-by-step explanation:

kherson [118]3 years ago

3 0

Answer:

what problem

Step-by-step explanation:

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Acellus: what is x= ? cm

vfiekz [6]

Answer:

To find x we use sine

Sine ∅ = opposite/ hypotenuse

x is the opposite

The hypotenuse is 15cm

sin 35° = x / 15

x = 15 sin 35°

x = 8.60

x = 9cm to the nearest tenth

Hope this helps you

3 0

3 years ago

Read 2 more answers

What is 60 over 40 in a mixed fraction

jeyben [28]

Answer:

1 1/2

Step-by-step explanation:

60/40 = (60 ÷ 20)/(40 ÷ 20) = 3/2; 3 > 2 => improper fraction Rewrite: 3 ÷ 2 = 1 and remainder = 1 => 3/2 = (1 × 2 + 1)/2 = 1 + 1/2 = = 1 1/2, mixed number (mixed fraction)

Hope this helped!

6 0

3 years ago

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What is the value of e in the equation below ?<br><br> 7(2e-1)-11=6+6e=

IrinaK [193]

14e-7=6+6e=8e=24=e=3

5 0

3 years ago

Find each product. Simplify if possible 2/3 x 5/6 x 14=

Ksenya-84 [330]

The product of the probllem is 21

7 0

4 years ago

Match the parametric equations with the verbal descriptions of the surfaces by putting the letter of the verbal description to t

alukav5142 [94]

Answer:

1. B

2. C

3. A

4. D

Step-by-step explanation:

The parametric equations of the circular cylinder are:

$x(u,v)=a\cos v\\y(u,v)=a\sin v\\z(u,v)=u$

If the orientation of the cylinder is changed to have the height $u$ along the x-axis, the parametric equations of the cylinder match:

$3. \mathbf{r} \left( u, v \right) = u \mathbf{i} + \cos v \mathbf{j} + \sin v \mathbf{k}$

The parametric equations of the circular paraboloid are:

$x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=u^2$

Using the units vectors the parametric equations match:

$1. \mathbf{r} \left( u, v \right) = u \cos v \mathbf{i} + u \sin v \mathbf{j} + u^{2} \mathbf{k}$

The parametric equations of the cone are:

$x(u,v)=au\cos v\\y(u,v)=au\sin v\\z(u,v)=u$

Using the units vectors and rotating the base of the cone from $z=0$ to $x=0$ the parametric equations match:

$2. \mathbf{r} \left( u, v \right) = u \mathbf{i} + u \cos v \mathbf{j} + u \sin v \mathbf{k}$

The equation left is the equation of a plane:

$4. \mathbf{r} \left( u, v \right) = u \mathbf{i} + v \mathbf{j} + \left( 2u - 3v \right) \mathbf{k}$

5 0

4 years ago