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ladessa [460]
3 years ago
5

Fill in the term that best completes the statement. Work transfers between objects.

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0

To fill in the term that best completes the statement, we have to realize the relationship between work and energy.

In general, the work done by an object on any other object is manifested as the change in the energy level of the two objects.

Thus, energy is transferred from one object to the other object when work is done by the former on the latter.

Therefore, term that best completes the statement is energy.

Hence our complete statement will be:

"Work transfers energy between objects".

PIT_PIT [208]3 years ago
5 0
Energy is the correct answer 

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Answer:

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Polar and cartesian equation<h2>Initial explanation</h2>

Let's analyze the relation between r and x and y:

We have that between the indicated value of r (of the polar coordinates) and x and y (of the cartesian coordinates) there is a relation because they form a triangle. If r changes, then the value of x and y will change.

<h2>STEP 1: given equation</h2>

Using the given equation

r = 2 secØ

we have that

\begin{gathered} r=2secØ \\ \downarrow \\ \frac{r}{2}=secØ \end{gathered}<h2>STEP 2: secØ equation</h2>

Observing the image of the initial explanation we have a right triangle, we know that the equation of

secØ for any right triangle is given by:

\sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}

In this case,

hypotenuse = r

adjacent side = x

then,

\begin{gathered} \sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}=\frac{r}{x} \\ \sec Ø=\frac{r}{x} \end{gathered}<h2>STEP 3: comparison between given equation and secØ equation</h2>

Then, we have that:

\begin{gathered} \sec Ø=\frac{r}{x} \\ \sec Ø=\frac{r}{2} \end{gathered}

This means that:

\begin{gathered} \frac{r}{x}=\sec Ø=\frac{r}{2} \\ \downarrow \\ \frac{r}{x}=\frac{r}{2} \end{gathered}

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
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What is the period for the function y = -4 cos (5x +3)? (4.3)
BlackZzzverrR [31]

The periodicity of function is \frac{2 \pi}{5}

<em><u>Solution:</u></em>

Given that we have to find the period of function

<em><u>Given function is:</u></em>

y = -4 + cos(5x+3)

<em><u>Use the below formula:</u></em>

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}

Thus,

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Now find the periodicity of cos(x)

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Thus the periodicity of function is \frac{2 \pi}{5}

4 0
3 years ago
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