All categories

3 years ago

A tiger leaps horizontally froma 7.5 m high rock with a speed of 3.0 m/s. How far from the base of the rock will she land?

Physics

1 answer:

nevsk [136]3 years ago

5 0

Answer:

<em>The tiger will land at 3.71 meters from the base of the rock</em>

Explanation:

<u>Horizontal Motion</u>

When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

$\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}$

The tiger leaps from a height of h=7.5 m with a speed of v=3 m/s. Substituting the values into the formula:

$\displaystyle d=3\cdot\sqrt{\frac {2\cdot 7.5}{9.8}}=3.71\ m$

The tiger will land at 3.71 meters from the base of the rock

You might be interested in

Some wave characteristics depend upon how the wave is produced. other wave characteristics depend upon the properties of the med

Anastaziya [24]

Waves have the characteristic that they can of transmit energy. This characteristic depend only on the medium and its properties. Electro-mechanical waves do not need medium to transfer its energy, is capable of transmitting it through empty space (vacuum).

<span>Mechanical waves require a medium in order to transport their energy. Sound waves are an example of mechanical way. They can not travel through vacuum. </span>

3 0

3 years ago

If a proton emits a photon in a spin-flipping event in a magnetic field, which is true?

vodomira [7]

Answer:

Explanation:

We know that the magnetic moment of electron is in same direction as it's spin so it's spin flip from down to up.

The correct answer is C that is . It flips from spin down to spin up.

5 0

3 years ago

Which of the following statements regarding the moon and Earth is correct?

hoa [83]

It’s Definitely A the other one’s are definitely wrong and I know A is a fact

7 0

2 years ago

Two illustrations of transverse waves. The one with shorter crests is labeled A. The wave with taller crests is labeled B. Which

suter [353]

The largest distance moved by a particle of a vibrating body from its equilibrium position is called amplitude. Wave B has higher energy because wave it has a higher amplitude.

<h3>What is the amplitude of a wave?</h3>

The largest distance moved by the particles on either side of the mean position is the amplitude of a wave.

The maximum height of either crest or trough from its equilibrium position is called amplitude.

Hence Wave B has higher energy because it has a higher amplitude.

To learn more about the amplitude of a wave refer to the link;

brainly.com/question/9351212

7 0

2 years ago

Read 2 more answers

1. An electron in an atom absorbs a photon with an energy of 2.38 eV and jumps from the n = 2 to n = 4 energy level in the atom.

oksian1 [2.3K]

1. $1.0\cdot 10^{-6}m$

First of all, let's convert the energy of the absorbed photon into Joules:

$E=2.38 eV \cdot (1.6\cdot 10^{-19}J/eV)=1.98\cdot 10^{-19} J$

The energy of the photon can be rewritten as:

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength of the photon

Re-arranging the formula, we can solve to find the wavelength of the absorbed photon:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.98\cdot 10^{-19} J}=1.0\cdot 10^{-6}m$

2. 1.24 eV

In this case, when the electron jumps from the n=4 level to the n=3 level, emits a photon with wavelength

$\lambda=1.66\cdot 10^{-6}m$

So the energy of the emitted photon is given by the formula used previously:

$E=\frac{hc}{\lambda}$

and using

$\lambda=1.66\cdot 10^{-6}m$

we find

$E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1.0\cdot 10^{-6}m}=1.99\cdot 10^{-19}J$

converting into electronvolts,

$E=\frac{1.99\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=1.24eV$

EDIT: an issue in Brainly does not allow me to add the last 2 parts of the solution - I have added them as an attachment to this post, check the figure in attachment.

7 0

3 years ago