A tiger leaps horizontally froma 7.5 m high rock with a speed of 3.0 m/s. How far from the base of the rock will she land?

Physics

1 answer:

nevsk [136]3 years ago

5 0

Answer:

<em>The tiger will land at 3.71 meters from the base of the rock</em>

Explanation:

<u>Horizontal Motion</u>

When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

$\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}$

The tiger leaps from a height of h=7.5 m with a speed of v=3 m/s. Substituting the values into the formula:

$\displaystyle d=3\cdot\sqrt{\frac {2\cdot 7.5}{9.8}}=3.71\ m$

The tiger will land at 3.71 meters from the base of the rock

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