Answer:
7m/s²
Explanation:
Given parameters:
Velocity at the top = 1m/s
Velocity at the bottom = 36m/s
Time = 5s
Unknown:
Average acceleration = ?
Solution;
Acceleration is the rate of change of velocity with time. It is expressed as;
A = 
v is the velocity at the top
u is the velocity at the bottom
t is the time taken
Now, insert the parameters and solve;
A = 
= 7m/s²
Answer:
A =150
I think it will help you bro
Mechanical advantage<span> <span>is a measure of the force amplification
achieved by using a tool, </span>mechanicaldevice or
machine system. Ideally, the
device preserves the input power and simply trades off forces against movement
to obtain a desired amplification in the output force. The model for this is
the law of the lever. So the ima is 3/1.5 = 2</span>
Answer:
Distance, S = 130m
Explanation:
Given the following data;
Initial velocity = 2m/s
Final velocity = 28m/s
Acceleration = 3m/s²
To find the distance, we would use the third equation of motion.
V² = U² + 2aS
Substituting into the equation, we have;
28² = 2² + 2*3*S
784 = 4 + 6S
6S = 784 - 4
6S = 780
S = 780/6
Distance, S = 130m
A :-) for this question , we should apply
F = GMm by d^2
( For making the calculation easy , first remove the decimals )
Given : G = 6.7 x 10^-11 Nm^2 / kg^2
= 67 x 10^-12 Nm^2 / Kg^2
M = 65 kg
m = 40 kg
d = 0.5 m
Solution -
F = GMm by d^2
F = 67 x 10^-12 x 65 x 40 by 0.5 x 0.5
F = 4355 x 40 x 10^-12 by 0.25
F = 174200 x 10^-12 by 0.25
F = 696800 x 10^-12
.:. The Gravitational force between mark and Katie is 696800 x 10^-12
