Question

Find the distance between -2-3i and 3+9i

Answer 1

Answer:

13

Step-by-step explanation:

We can consider the complex number $x+iy$ as point with coordinates $(x,y),$ where $x$ is real part of the complex number and $y$ is an imaginary part of the complex number.

The distance between two complex numbers is exactly tha distance between two points corresponding to each number.

$z_1=-2-3i\Rightarrow A(-2,-3)\\ \\z_2=3+9i\Rightarrow B(3,9)$

Now find the distance between A and B:

$AB=\sqrt{(-2-3)^2+(-3-9)^2}=\sqrt{(-5)^2+(-12)^2}=\sqrt{25+144}=\sqrt{169}=13\ units$