Ask question

Ask question

All categories

2 years ago

9

According to the rational root theorem, the numbers below are some of the potential roots of f(x) = 10x3 29x2 – 66x 27. select a

ll that are actual roots.

1 answer:

exis [7]2 years ago

6 0

The actual roots of the function $f(x)=10x^{3}+29x^{2} -66x+27$ are -9/2, 3/5 and 1.

Given function $f(x)=10x^{3}+29x^{2} -66x+27$ .

Function is a relationship between two or more variables expressed in equal to form.

The roots of a polynomial function are the zeroes of the polynomial function. A polynomial function is a function that involves only non negative integer powers in an equation.

The polynomial function is given as:

$f(x)=10x^{3}+29x^{2} -66x+27$

factorize the above function

$f(x)=(2x+9)(5x-3)(x-1)$

Now put the function f(x) equal to zero.

f(x)=(2x+9)(5x-3)(x-1)

split the function means put all the expressions equal to zero as under:

(2x+9)(5x-3)(x-1)=0

solve each for the value of x

x=-9/2,x=3/5,x=1

Hence the roots of the function $f(x)=10x^{3} +29x^{2} -66x+27$ are which are also the values of x are -9/2,3/5,1.

Learn more about function at brainly.com/question/10439235

#SPJ4

You might be interested in

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

4 years ago

Explain how you can write 35% as the sum of two benchmark percents or as a multiple of a percent

OlgaM077 [116]

I'll just take the points thanks XD

3 0

3 years ago

100 POINTS FOR THIS!!!

OLga [1]

Answer:

b 56°

a 71°

d 19°

c 127°

dum dadummm dumm dududu

4 0

3 years ago

Read 2 more answers

Ming paid $8 for every item except peppers. was her bag lighter than or heavier than 4 pounds? show addition using as few steps

denis23 [38]

If there was a chart with this that would be helpful but at this time with the information you have given you can not solve this problem

4 0

3 years ago

Which is equal to P-R?

lorasvet [3.4K]

<h3>Answer: Choice B</h3>

With matrix subtraction, you simply subtract the corresponding values.

I like to think of it as if you had 2 buses. Each bus is a rectangle array of seats. Each seat would be a box where there's a number inside. Each seat is also labeled in a way so you can find it very quickly (eg: "seat C1" for row C, 1st seat on the very left). The rule is that you can only subtract values that are in the same seat between the two buses.

So in this case, we subtract the first upper left corner values 14 and 15 to get 14-15 = -1. The only answer that has this is choice B. So we can stop here if needed.

If we kept going then the other values would be...

row1,column2: P-R = -33-16 = -49

row1,column3: P-R = 28-(-24) = 52

row2,column1: P-R = 42-25 = 17

row2,column2: P-R = 35-(-30) = 65

row2,column3: P-R = -19-36 = -55

The values in bold correspond to the proper values shown in choice B.

As you can probably guess by now, matrix addition and subtraction is only possible if the two matrices are the same size (same number of rows, same number of columns). The matrices don't have to be square.

7 0

3 years ago