Question

According to the rational root theorem, the numbers below are some of the potential roots of f(x) = 10x3 29x2 – 66x 27. select all that are actual roots.

Answer 1

The actual roots of the function $f(x)=10x^{3}+29x^{2} -66x+27$ are -9/2, 3/5 and 1.

Given  function $f(x)=10x^{3}+29x^{2} -66x+27$.

Function is a relationship between two or more variables expressed in equal to form.

The roots of a polynomial function are the zeroes of the polynomial function. A polynomial function is a function that involves only non negative integer powers in an equation.

The polynomial function is given as:

$f(x)=10x^{3}+29x^{2} -66x+27$

factorize the above function

$f(x)=(2x+9)(5x-3)(x-1)$

Now put the function f(x) equal to zero.

f(x)=(2x+9)(5x-3)(x-1)

split the function means put all the expressions equal to zero as under:

(2x+9)(5x-3)(x-1)=0

solve each for the value of x

x=-9/2,x=3/5,x=1

Hence the roots of the function $f(x)=10x^{3} +29x^{2} -66x+27$ are which are also the values of x are -9/2,3/5,1.

Learn more about function at brainly.com/question/10439235

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