Let Z be a random variable following the standard normal distribution with mean µ = 0 and standard deviation σ = 1.
The 67th percentile of the distribution is the value z that separates the bottom 67% of the distribution from the top 100% - 67% = 33%. In terms of probability, we have
Pr[Z ≤ z] = 0.67
Use the inverse CDF for the normal distribution (or lookup z scores in a table) to find
z = ɸ⁻¹(0.67) ≈ 0.4399
where ɸ(z) is the CDF for the normal distribution.
Answer:
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Explanation:
Answer:
For example, the U.S. Census Bureau defines a family in the following manner: "A family is a group of two people or more (one of whom is the householder) related by birth, marriage, or adoption and residing together."
Explanation:
Answer:
Explanation:Jews
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Answer:
z = 1.00
Explanation:
Given:
Probability of z value = 0.6826
By using standard normal table for z value.
P(-z < Z < z) = 0.6826
P(Z < z) - P(Z < -z) = 0.6826
We know that
P(Z < z) + P(Z < -z) = 1
So,
2P(Z < z) - 1 = 0.6826
2P(Z < z) = 1 + 0.6826
2P(Z < z) = 1.6826
P(Z < z) = 1.6826 / 2
P(Z < z) = 0.8413
So,
P(Z < 1.00) = 0.8413
z = 1.00
