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levacccp [35]
4 years ago
12

Find the value of z such that

SAT
1 answer:
Reika [66]4 years ago
5 0

Answer:

z = 1.00

Explanation:

Given:

Probability of z value  = 0.6826

By using standard normal table for z value.

P(-z < Z < z) = 0.6826

P(Z < z) - P(Z < -z) = 0.6826

We know that

P(Z < z) + P(Z < -z) = 1

So,

2P(Z < z) - 1 = 0.6826

2P(Z < z) = 1 + 0.6826

2P(Z < z) = 1.6826

P(Z < z) = 1.6826 / 2

P(Z < z) = 0.8413  

So,

P(Z < 1.00) = 0.8413  

z = 1.00

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In a study of helicopter usage and patient survival, among the 56,074 patients transported by helicopter, 235 of them
xxMikexx [17]

Using the hypergeometric distribution, it is found that the probability is 0.845 = 84.5%.

--------------------

  • The patients are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

Combination formula:

is the number of different combinations of x objects from a set of n elements, given as:

C_{n,x} = \frac{n!}{x!(n-x)!}

--------------------

  • 56074 patients, thus N = 56074
  • Sample of 40, thus, n = 40
  • 235 left against medical advice, thus, k = 235.

The probability that none left against medical advice is P(X = 0), so:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,56074,40,235) = \frac{C_{235,0}*C_{55839,40}}{C_{56074,40}} = 0.845

The probability is 0.845 = 84.5%.

A similar problem is given at brainly.com/question/24008577

6 0
2 years ago
Is this statement true or false? Samuel Gompers had the same goals for the labor movement as the socialists and anarchists did.
igor_vitrenko [27]

Answer:

<h2>TRUE</h2>

Explanation:

sana makatulong♥️

6 0
3 years ago
Point (20, 5) is on the graph of inverse variation. Which of the following ordered pair is on the graph?.
Bess [88]

The point (10, 10) is on the graph.

<h3>Procedure - Inverse variation</h3><h3 /><h3>Inverse variation model</h3><h3 />

An <em>inverse</em> variation is represented by the following formula:

y = \frac{k}{x} (1)

Where:

  • x - Independent variable.
  • y - Dependent variable.
  • k - Proportionality constant.

We can eliminate the proportionality constant by creating the following relationship:

x_{1}\cdot y_{1} = x_{2}\cdot y_{2} (2)

<h3>Determination of another point</h3>

If we know that x_{1} = 20, y_{1} = 5 and x_{2} = 10, then the remaining variable is:

y_{2} = \left(\frac{x_{1}}{x_{2}} \right)\cdot y_{1}

y_{2} = \left(\frac{20}{10} \right)\cdot (5)

y_{2} = 10

The point (10, 10) is on the graph. (Correct choice: C) \blacksquare

To learn more on inverse variations, we kindly invite to check this verified question: brainly.com/question/4838941

<h3>Remark</h3>

The statement is incomplete. Complete form is described below:

<em>Point </em>(20, 5)<em> is on the graph of an inverse variation. Which of the following ordered pair is on the graph? </em><em>A.</em><em> </em>(4,1)<em>, </em><em>B.</em><em> </em>(2, 25)<em>, </em><em>C.</em><em> </em>(10, 10)<em>, </em><em>D.</em><em> </em>(16, 4)<em>.</em>

7 0
2 years ago
Why is astronomy considered the first science
maksim [4K]

Answer:

Astronomy is one of the oldest sciences

5 0
3 years ago
The number of work stoppages in the automobile industry for selected monthes are 6,0,10,14,8,0 .What is the median number and wh
Ratling [72]

Answer: median is 7, the type of mode is unimodal

Explanation:

median is 7 because there are 6 numbers. Based on the rules if the number of scores is even then get the two middle most numbers (after arranging the scores in increasing order) then get the average so 6 + 8 is 14 and the average is 7.

the mode is most occured number. So the most occured number is 0. And since we only have 1 type of number occured more than one time so that is unimodal.

3 0
3 years ago
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