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3 years ago

Name two pairs of pallel lines in the figure

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

6 0

I didn’t post a figure but if u do I’ll be glad to help :)

Reika [66]3 years ago

4 0

What figure you didn't post it???

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Question 5^ Need help ... ASAP ... your help is really appreciated ...

goblinko [34]

Answer:

See below

Step-by-step explanation:

I think we had a question similar to this before. Again, let's figure out the vertical and horizontal distances figured out. The distance from C at x=8 to D at x=-5 is 13 units while the distance from C at y=-2 to D at y=9 is 11 units. (8+5=13 and 2+9=11, even though some numbers are negative, we're looking at their value in those calculations)

Next, we have to divide each distance by 4 so we can apply it to the ratio. 13/4= $\frac{13}{4}$ and 11/4= $\frac{11}{4}$ . Next, we need to read the question carefully. It's asking us to place the point in the ratio 3 to 1 from C to D. The point has to be closer to endpoint D because of this. Let's take each of our fractions, multiply them by 3, then add them towards the direction of endpoint D to get our answer (sorry if that sounds confusing):

$\frac{13}{4}*3 = \frac{39}{4}\\ 8-\frac{39}{4} = \frac{-7}{4}\\\frac{11}{4}*3 = \frac{33}{4} \\-2+\frac{33}{4} = \frac{25}{4}$

Therefore, our point that partitions CD into a 3:1 ratio is ( $\frac{-7}{4}, \frac{25}{4}$ ).

I'm not sure if there was more to #5 judging by how part B was cut off. From what I can understand of part B, however, I believe that Beatriz started from endpoint D and moved towards C, the wrong direction. She found the coordinates for a 1:3 ratio point.

Also, for #6, since a square is a 2-dimensional object, the answer needs to be written showing that. The answer for #6 is 9 units^2.

7 0

3 years ago

Nick has tennis practice every sixth day. Mark has tennis practice every 4th day. On July 31st they both had tennis practice. Wh

Montano1993 [528]

Nick has tennis practice every sixth day = 6

Mark has tennis practice every 4th day = 4

They both had tennis practice on = 31st July

We have to find when will be the next time that they both have practice on the same day?

For this, we will find the LCM of 4 and 6

So, LCM of 4 and 6 is 12.

So, it will be 12 days after 31st July, that they will practice on the same day.

So it is 12th August.

3 0

3 years ago

In the data set, what is the variance? 6 8 1 9 4

Juli2301 [7.4K]

The answer is s² ≈ 10.3

3 0

3 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

Slope:

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

Slope:

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

3 years ago

What key features are necessary and how they can be used to create the sketch of a polynomial function?

Tomtit [17]

The key features of polynomials are the vertex, axis of symmetry, x and y intercepts.

1. The degree will help you find the end behavior.

2. The vertex shows you where it changes concavity.

3. X and y intercepts give you a couple of points of reference.

4. Axis of symmetry is only applicable to even degree polynomials.

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

4 0

2 years ago