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maksim [4K]
3 years ago
12

Human body temperatures are normally distributed with a mean of 98.20°F and a standard deviation of 0.62°F. If 19 people are ran

domly selected, find the probability that their mean body temperature will be less than 98.50°F.
Mathematics
2 answers:
Luden [163]3 years ago
7 0

Answer:

.9826

Step-by-step explanation:

gradpoint

Mademuasel [1]3 years ago
4 0

Answer:

Step-by-step explanation:

Z = (x-µ)/(s/√n)=(98.5-98.2)/(0.62/√19) = 2.11

left tail p-value = 0.9826

so 98.26% are lower.

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{ \rm{m =  \frac{ {x}^{3} }{8}  + 16}} \\

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{ \rm{8m =  {x}^{3}  + 128}} \\  \\ { \rm{ {x}^{3} = 8m - 128 }} \\  \\ { \rm{ {x}^{3} = 8(m - 16) }} \\  \\ { \rm{x =  \sqrt[3]{8}  \times  \sqrt[3]{(m - 16)} }} \\  \\ { \rm{x = 2 \sqrt[3]{(m - 16)} }}

• therefore:

{ \boxed{ \rm{ {f}^{ - 1} (x) = 2 {(m - 16)}^{ \frac{1}{3} } }} }\\

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