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maksim [4K]
3 years ago
12

Human body temperatures are normally distributed with a mean of 98.20°F and a standard deviation of 0.62°F. If 19 people are ran

domly selected, find the probability that their mean body temperature will be less than 98.50°F.
Mathematics
2 answers:
Luden [163]3 years ago
7 0

Answer:

.9826

Step-by-step explanation:

gradpoint

Mademuasel [1]3 years ago
4 0

Answer:

Step-by-step explanation:

Z = (x-µ)/(s/√n)=(98.5-98.2)/(0.62/√19) = 2.11

left tail p-value = 0.9826

so 98.26% are lower.

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What is the equation of the line that passes through the point (-4,-8)(−4,−8) and has a slope of 4
elena-s [515]

Answer:

y=4x+8

Step-by-step explanation:

8 0
3 years ago
Which number line shows the solutions to x > 5?
Montano1993 [528]
D I think so, I might be wrong tho
8 0
2 years ago
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Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r), what is r if c/c’ = 5 and d' = 20?
PtichkaEL [24]
The answer to your problem is. C)50
7 0
3 years ago
What is the solution of the system?
spin [16.1K]
The Answer is b: x = 18, y = -20

Proof:

Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{7 x + 5 y = 26 | (equation 2)

Swap equation 1 with equation 2:
{7 x + 5 y = 26 | (equation 1)
{4 x + 3 y = 12 | (equation 2)

Subtract 4/7 × (equation 1) from equation 2:
{7 x + 5 y = 26 | (equation 1)
{0 x+y/7 = (-20)/7 | (equation 2)

Multiply equation 2 by 7:
{7 x + 5 y = 26 | (equation 1)
{0 x+y = -20 | (equation 2)

Subtract 5 × (equation 2) from equation 1:
{7 x+0 y = 126 | (equation 1)
{0 x+y = -20 | (equation 2)

Divide equation 1 by 7:
{x+0 y = 18 | (equation 1)
{0 x+y = -20 | (equation 2)

Collect results:

Answer: {x = 18, y = -20
6 0
3 years ago
Which of these is not a possible r-value?
Y_Kistochka [10]

Answer:

a. 1.75

Step-by-step explanation:

r values, or the correlation coefficient  must be between -1 and 1, inclusive

-1 is a perfect negative correlation

0 is no correlation

+1 is a perfect positive correlation

1.75 is not between -1 and 1

7 0
3 years ago
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