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3 years ago

The ratio of dark chocolate candies to white chocolate candies is 4 to 3.

Mathematics

1 answer:

Elena L [17]3 years ago

3 0

The answer is 18 are white chocolate.

Here is my proof

4 × 6 = 24 and 3 × 6 = 18 and I got 4 and 3 from the ratio of dark chocolate candies to white chocolate candies and I got the 6 from the multiplication chart that they both end up with the same number which is 6. So 18 is the answer

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Simplify 6x^2/ cubed root of 3x

hammer [34]

Answer:

6x^2/(3x)^1/3

6= 3 .2

So, 3.2 (x^2)/( 3^1/3) x^1/3

=3^2/3)(2). x^5/3

={ 2 .( 3)^2/3 } x^5/3

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3 years ago

△STR≅△LMN, SR=7b+8, and LN=11b−12. Find b and SR.

mote1985 [20]

Answer:

b = 5

Step-by-step explanation:

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3 years ago

Please help with #12 im confused that is the key but i dont get it

Svetllana [295]

Given Equation

$\boxed{ \tt \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})}$

Step by step expansion:

$\dashrightarrow \sf \: (8 \sqrt{3} - 2 \sqrt{2} )(8 \sqrt{3} + 2 \sqrt{2})$

$\\ \\$

$\dashrightarrow \sf \: (8 \sqrt{3})^{2} - (2 \sqrt{2} {)}^{2}$

Reason:

(a + b)(a - b) = a²- b²

$\\ \\$

$\dashrightarrow \sf \: (8 {}^{2} \times { \sqrt{3} }^{2} )- (2 \sqrt{2} {)}^{2}$

$\\ \\$

$\dashrightarrow \sf \: (64 \times 3 ) - (2 \sqrt{2} {)}^{2}$

$\\ \\$

$\dashrightarrow \sf \: (64 \times 3 ) - (2 {}^{2} \times \sqrt{2} {}^{2} {)}$

$\\ \\$

$\dashrightarrow \sf \: 192- 8$

$\\ \\$

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~BrainlyVIP ♡

4 0

2 years ago

Read 2 more answers

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Hi, Guys This is Math 5th Grade I was Doing my homeWork when I did not know a question and I decided maybe 1 of you guys can hel

alexgriva [62]

Answer:

Circle A's attributes were used to be organized because both shapes have a right angle. Circle B's attributes were used to be organized because both shapes have 2 sets of parallel lines that are across from each other. The middle was organized because both shapes have 2 sets of parallel lines and 4 right angles.

Step-by-step explanation:

Let me know if this helps!

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2 years ago