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iVinArrow [24]
3 years ago
11

Is 2/3 and 8/12 in equivalent ratio

Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer: if your question here is if they are the same since it says equivalent then yes

Step-by-step explanation: 2/3 = 8/12

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Step-by-step explanation:

I think no. c is correct

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Answer:

A.

Step-by-step explanation:

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The diameter of a circular chip is doubled to use in a new board game. The area of the new chip will be
nikitadnepr [17]

Answer: A_2=\frac{\pi(2D)^{2}}{4}


Step-by-step explanation:

1. You have the following formula for calculate the area of the original circular chip:

A_1=\frac{\pi(D)^{2}}{4}

Where D is the diameter of the circle.

2. Then, if the diameter of the original circular chip is doubled (2D) to use in a new board game, the area of the new chip can be calculated with the following formula:

A_2=\frac{\pi(2D)^{2}}{4}


7 0
3 years ago
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Kwame says that the ordered pair(5,0) is on the y-axis. So you agree? Justify your answer.
RideAnS [48]

Answer:

No, the answer would be on the x-axis. This is because x=5 and y=0, which would mean that the ordered pair (5,0) would be on the x-axis.

Hope this helps!

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3 years ago
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Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B
Galina-37 [17]

Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

8 0
3 years ago
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