11. |6- 15| - |5(-4)|= ? A.-29 B. -11 C. 1 D. 11 E. 29
1 answer:
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Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P( >
) = 0.05
P(Z > ) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;
x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
Answer:
Step-by-step explanation:
Given function is,
f(x) =
If the given function is vertically stretched by a scale factor of Or 1.5,
Transformed function will be,
h(x) =
h(x) =
Further function 'h' is shifted 1 units upwards,
g(x) = h(x) + 1
g(x) =
Domain of the function → x ≥ 0 Or [0, ∞)
Range of the function → y ≥ 1 Or [1, ∞)
Transformations done → Parent function f(x) is vertically stretched by a scale factor of then shifted 1 unit upward.
