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3 years ago

Could you help me with one Algebra problem?

1 answer:

3 0

The solutions are
1. If A=B implies c = then A ∪ B = B
2. If B is inside A e = then A ∩ B = B
3. A ∪ Ø implies d = A
4. A ∩ Ø imiplies a = Ø
5. B ∪ Ø implies b = B

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A farmer has a rectangular field.the field is 300m long and 200m wide. calculate the perimeter of the field

tangare [24]

Answer:

1000m

STEP BY STEP EXPLANATION: 300m+300m+200m+200m

=600m+400m

=1000m

4 0

3 years ago

Tyler read 15 pages of a book. Ann read 9 pages of the same book. Did tyler read 4 more pages than Ann?. Explain

Marysya12 [62]

No because Tyler read 15 pages and 9 plus 4 is 13 fewer then what Tyler read

7 0

3 years ago

Read 2 more answers

PROBLEM: Riley has a rectangular shaped patio that is 13 feet long by 15 feet wide. He wants to DOUBLE THE AREA of the patio by

photoshop1234 [79]

Answer:

1) The equation that represents the total area of Riley's proposed ratio is $A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y)$ .

2) The length and width of the new patio are approximately 18.4 feet and 21.2 feet, respectively.

Step-by-step explanation:

1) From Geometry we remember that area formula for the rectangle is represented by:

$A = x\cdot y$ (1)

Where:

$A$ - Area, measured in square feet.

$x$ - Length, measured in feet.

$y$ - Width, measured in feet.

From statement we know that Riley wants to double the area, that is:

$A' = 2\cdot A$ (2)

By applying (1) in (2), we get the following expression:

$A' = 2\cdot x\cdot y$ (3)

Given that Riley wants to double the area of the pation by increasing the length and width by the same amount, we can rearrange (3) by algebraic means:

$A' = \sqrt{2}\cdot \sqrt{2}\cdot x\cdot y$

$A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y)$ (3b)

The equation that represents the total area of Riley's proposed ratio is $A' = (\sqrt{2}\cdot x)\cdot (\sqrt{2}\cdot y)$ .

2) If we know that $x = 13\,ft$ and $y = 15\,ft$ , then the length and the width of the new patio are, respectively:

$x' = \sqrt{2}\cdot x$

$x' = \sqrt{2}\cdot (13\,ft)$

$x' \approx 18.4\,ft$

$y' = \sqrt{2}\cdot y$

$y' = \sqrt{2}\cdot (15\,ft)$

$y' \approx 21.2\,ft$

The length and width of the new patio are approximately 18.4 feet and 21.2 feet, respectively.

8 0

3 years ago

What is the standard form of the equation Center (-14,5), circumference: 22π

IRISSAK [1]

The standard equation for a circle with center at (h,k) and radius r is

(x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle.

The formula for the circumference of a circle is C = 2pi*r. In this particular problem, we need to determine the radius of the circle. That radius is: r = C/[2pi]. Here, C = 22pi, so we get r = 22pi/[2pi], and so r^2 = 11^2.

Putting to use the given info, we have:

(x+14)^2 + (y-5)^2 = 11^2

6 0

3 years ago

3. Your school has been running a nickel drive to raise money for a sister school

lisabon 2012 [21]

A- 678.25 grams
B- 200 grams
C- 5 rolls

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3 years ago