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drek231 [11]
3 years ago
11

Solve the following systems: 3x+4y=0 2x+3y=1

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

Answer is x= -4 and y= 3

Step-by-step explanation:

given \: equations \: are \\ 3x + 4y = 0 \:  \: and \: 2x + 3y = 1  \\ multiply \: by \: 2 \: in \: first \: equation \\ 6x + 8y = 0 \\ multiply \: by \: 3 \: in \: second \: equation \\ 6x + 9y = 3 \\ subtracting \: the \: above \: mentioned \: equation \:  \\  we \: get \:  - y =  - 3 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  y = 3 \\ substitute \: y = 3 \: in \: first \: equation \\ 3x + 4(3) = 0 \\ 3x =  - 12 \\ x =  - 4

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