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goldfiish [28.3K]
3 years ago
9

If cos theta = 3/5 then tan theta =

Mathematics
1 answer:
algol133 years ago
7 0

Answer:

3 √5

Step-by-step explanation:

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A photograph is 8 centimeters wide. After Kari enlarges the photograph, it is 3 times as wide as the original. How wide is the p
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-2.8 repeating as a fraction
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0.8888888 = 8/9
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A jar contains only​ pennies, nickels,​ dimes, and quarters. There are 29 ​pennies, 13 ​dimes, and 21 quarters. The rest of the
aleksklad [387]

Answer:

First Question: <u>63 coins are not nickels.</u>

Second Question: <u>63+n=91</u>

Step-by-step explanation:

For your first question: 29+21=50 and 50+13=63. 63 coins are not nickels.

For your second question: You can do 29+21+13+n=91, I just simplified and said 63+n=91. You can choose.

Hope that this helps! Good luck with what you're working on!

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Step-by-step explanation:

5 0
3 years ago
Please help with this Math Question...
Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 |   1   4   7   6

   <u>|   ↓  -2  -4  -6</u>

       1    2    3   0 ← remainder is 0 so x = -2 is a root  ⇒  (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}

x=\dfrac{-2\pm\sqrt{4-12} }{2}

x=\dfrac{-2\pm\sqrt{-8} }{2}

x=\dfrac{-2\pm2i\sqrt{2}}{2}

x = -1 \pm i\sqrt{2}

x = -1 + i\sqrt{2}       x = -1 - i\sqrt{2}

x - (-1 + i\sqrt{2})=0       x - (-1 - i\sqrt{2})=0

The factors are:

(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]




5 0
3 years ago
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