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2 years ago

15

HELP!!!!In 2004, school lunch Rockwell high school was $2.20.In 2009 the costs increased to $3.25. Find the annual rate of chang

e in the price for school lunch from 2004 to 2009.
a. $0.20 per year
b. $0.21 per year
c. $1.05 per year
d. $0.18 per year

1 answer:

arsen [322]2 years ago

5 0

Answer:

$0.21 per year

Step-by-step explanation:

$0.21 times 5 years equals $1.05

So its $0.21

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What is a correlation

posledela

Answer: a relationship/connection between two variables, there are negative and positive correlations.

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2 years ago

Select all the points that are on the line through (0 5) and (2 8) A.(5 11) B.(5 10) C.(6 14) D.(30 50) E.(40 60)

mihalych1998 [28]

Answer:

Options C. and D. are correct.

Step-by-step explanation:

Let $(x_1,y_1)=(0,5),\,(x_2,y_2)=(2,8)$

Equation of a line is given by $y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)$

$y-5=(\frac{8-5}{2-0})(x-0)\\\\y-5=\frac{3}{2}x\\\\2y-10=3x\\3x-2y+10=0$

Put $(x,y)=(5,11)$

$3(5)-2(11)+10=15-22+10=3\neq 0$

Put $(x,y)=(5,10)$

$3(5)-2(10)+10=15-20+10=5\neq 0$

Put $(x,y)=(6,14)$

$3(6)-2(14)+10=18-28+10=0$

Put $(x,y)=(30,50)$

$3(30)-2(50)+10=90-100+10=0$

Put $(x,y)=(40,60)$

$3(40)-2(60)+10=0\\120-120+10=10\neq 0$

So, points $(6,14),\,(30,50)$ satisfy the equation $3x-2y+10=0$

Therefore,

points $(6,14),\,(30,50)$ lie on the line through $(0,5)$ and $(2,8)$

Options C. and D. are correct.

8 0

2 years ago

0.5, 3/16, 5/48 in order from least to greatest

sukhopar [10]

1# 5/48
2# 0.5
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3 years ago

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a

Anit [1.1K]

Answer:

Analyzed and Sketched.

Step-by-step explanation:

We are given $y=\frac{\ln\left(5x)}{x^2}$

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

$y'=\frac{1-2\ln\left(5x)}{x^3}=0$

$x = \sqrt e/5$ is absolute maximum

$y''=\frac{6\ln\left(5x)-5}{x^4}=0$

$x=e^{5/6}/5$ is the point concavity changes from down to up.

Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.

The graph is given in the attachment.

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3 years ago

At The Last Book Store, 4 books cost $28. How many books could you buy for $49?

Mila [183]

7

You divide 28 by 4 and get 7. Then you divide 49 by whatever you get.

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2 years ago