The excess reactant in the combustion of 211 g of methane in an open atmosphere is oxygen, O₂
<h3>What is a combustion reaction? </h3>
A combustion reaction is a reaction in which a substance burns in air (oxygen) to produce carbon dioxide and water.
<h3>Combustion of methane </h3>
Methane combust in air (oxygen) to produce carbon dioxide and water according to the following equation:
CH₄ + 2O₂ —> CO₂ + 2H₂O
From the question given above, we were told that 211 g of methane combust in an open atmosphere. This simply means that the amount of oxygen will be very high.
Therefore, we can conclude that oxygen will be the excess reactant since the reaction is carried out in an open atmosphere.
Learn more about stoichiometry:
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Answer:
Explanation:
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Based on the financial data (information) provided in the table (see attachment) and assuming a total fixed cost (TFC) of $5, the business firm's: B. economic profit is equal to $16, .
<h3>What is an economic profit?</h3>
An economic profit can be defined as a measure of the difference between the total revenue that a business firm (economic entity) has received from the sales of its products (outputs) and the opportunity costs of its inputs.
This ultimately implies that, an economic profit is equal to the total revenue minus total cost. Thus, it typically involves subtracting the total cost of a product from the total revenue that a business firm (economic entity) receives through it sales.
Based on the financial data (information) provided in the table (see attachment), we can infer and logically deduce that business firm's economic profit is equal to $16, assuming a total fixed cost (TFC) of $5.
Read more on profit here: brainly.com/question/13800671
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<h2>✏Answer ✏</h2>
<em>The short answer is to reduce the uncertainty in your measurement of the period. ... If you are using a stopwatch and manual timing- then your uncertainty in timing an interval is likeley to be about say 0.2 s . If the period of the pendulum is about 1 second then 0.2 s uncertainty corresponds to about 20% .</em>
Explanation:
<em>#</em><em> </em><em>Brainliest Bunch</em><em> </em>
Answer:
kilometers/second per million parsecs
Explanation:
It is sometimes called Hubble time
It is what astronomers use for the Hubble constant
