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MAXImum [283]
3 years ago
7

50 points :) 100-70=?

Mathematics
2 answers:
Marina86 [1]3 years ago
3 0

Answer:

30

Step-by-step explanation:

Did you just do this for fun?

Either way have a good rest of your day!

abruzzese [7]3 years ago
3 0

Answer:

THANK YOU!!!  

30

I really appreciate this  have a great day

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(-2)(6cd)(-c)<br> Help please!! I'm totally lost on this question!!
mariarad [96]
(c*c6). hope it helps
8 0
3 years ago
The angle measurements in the diagram are represented by the following expressions.
Free_Kalibri [48]

Answer:

x = 12

m(∠B) = 45°

Step-by-step explanation:

Given question is incomplete; find the complete question in the attachment.

In the figure attached two lines 'l' and 'm' are the parallel lines and line 'n' is a transverse.

Angles A and B are the "Alternate exterior angles" which will equal in measure.

m(∠A) = m(∠B)

(5x - 15) = (2x + 21)

5x - 2x = 15 + 21

3x = 36

x = 12

Since, m(∠B) = (2x + 21)

                     = (2×12) + 21

                     = 24 + 21

                     = 45°

Therefore, x = 12 and measure of angle B will be 45°.

6 0
3 years ago
The sum of nine times a number, and 4, is equal to eight times the number.
pishuonlain [190]

Answer:

-4

Step-by-step explanation:

Let's put this in math notation. We can call the number x:

9x+4=8x

Subtract 8x from both sides:

x+4=0

Subtract 4 from both sides:

x=-4

4 0
2 years ago
Read 2 more answers
The perimeter of the triangle shown on the right is 257 feet.
Alexeev081 [22]
242wjshsjshshshshsshsnsbsbs
5 0
2 years ago
A cylindrical bucket is being filled with paint at a rate of 4 cm3 per minute. How fast is the level rising when the bucket star
andre [41]

Answer:

Therefore,the level of paint is rising when the bucket starts to overflow at a rate  \frac{1}{100\pi} cm per minute.

Step-by-step explanation:

Given that, at a rate 4 cm³ per minute,a cylinder bucket is being filled with paint

It means the change of volume of paint in the cylinder is 4 cm³ per minutes.

i.e \frac{dV}{dt}= 4 cm³ per minutes.

The radius of the cylinder is 20 cm which is constant with respect to time.

But the level of paint is rising with respect to time.

Let the level of paint be h at a time t.

The volume of the paint at a time t is

V=\pi r^2 h

\Rightarrow V=\pi (20)^2h

\Rightarrow V=400\pi h

Differentiating with respect to t

\frac{dV}{dt}=400\pi \times \frac{dh}{dt}

Now putting the value of \frac{dV}{dt}

\Rightarrow 4=400\pi \frac{dh}{dt}

\Rightarrow \frac{dh}{dt}=\frac{4}{400\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{100\pi}

To find the rate of the level of paint is rising when the bucket starts to overflow i.e at the instant h= 70 cm.

\left \frac{dh}{dt}\right|_{h=70}=\frac{1}{100\pi}

Therefore, the level of paint is rising when the bucket starts to overflow at a rate \frac{1}{100\pi} cm per minute.

4 0
3 years ago
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