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3 years ago

A set of prime number between 5 and 15.express it in listing and setbuilder methods

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

7 0

Answer:

A set of prime number between 5 and 15.

Listing method:{ 7,11,13}

Set builder method:{X:X is a set of prime number between 5 and 15}

In listing method,the elements are listed inside the brackets.Listing method are also called rooster method.

In set builder method,the elements are represented by a variable stating their common properties.Set builder method are also called rule method.

Hope this helps...

Good luck on your assignment..

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What is the answer help

Dominik [7]

Answer:

X=50

Step-by-step explanation:

15×2=30

25×2=50

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3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

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3 years ago

What is the solution to the expression Negative 2 minus 3 minus (negative 4)?

m_a_m_a [10]

Answer:

negative 1.................

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4 years ago

Read 2 more answers

The bigger of two numbers is four more

Otrada [13]

Answer:

X=the smaller

y=the larger

The bigger of two numbers is four more than the smaller, then:

y=x+4

one more than twice the smaller is the same as the larger, then

1+2x=y

We have the following system of equations:

y=x+4

y=2x+1

We solve this system by equal values method:

x+4=2x+1

x-2x=1-4

-x=-3

x=3

We find the value of "y"now:

y=x+4

y=3+4

y=7

the values of x and y are:

x=3

y=7

Step-by-step explanation:

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4 years ago

I need the answer asap

aliina [53]

Answer:What the question?

Step-by-step explanation:

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3 years ago

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A set of prime number between 5 and 15.express it in listing and setbuilder methods​

A set of prime number between 5 and 15.express it in listing and setbuilder methods