So we are given an initial equation of: 
.
We are told that a new path is going to be perpendicular to this line. So to find a slope that is perpendicular to a line, we take the slope of the known line (in this case 2) and we flip it and change the sign. So since this slope is essentially 
, we are going to flip it to make it 
and change the sign to make it 
.
So now we know that the slope of the perpendicular line is , we can start a new equation for this line:
We are also told that the path will intersect at (-2,-3) - this is a solution to the two lines. So to find b in this new equation, let's plug in the x and y values found in the point:
Then solve for b:
So then we plug in our value for b and leave x and y:
So this equation now represents the new path.
Consider the complete question is "The equation of the line 
is y=5x+1 and the equation of line 
is 2y-10x+3=0. How can you show that these two lines are parallel?"
Given:
Equation of is 
.
Equation of is 
.
To show:
The these line as parallel.
Solution:
We have,
...(i)
...(ii)
Equation (ii) can be written as
...(iii)
Slope intercept form of a line is
...(iv)
where, m is slope and b is y-intercept.
On comparing (i) with (iv), we get slope of line .
On comparing (iii) with (iv), we get slope of line .
Since, 
, therefore, lines and and parallel because slope of two parallel lines are always equal.
Hence proved.
It’s C I think but correct me if I’m wrong
Answer: See explanation
Step-by-step explanation:
You didn't give the options relating to the question.
To solve this first, you need to know that we have to note that (+) × (-) = (-). Therefore, 1.25+(-0.75) will be thesame as writing 1.25 - 0.75. This will then be:
= 1.25 - 0.75
= 0.50
Since it's a square, the sides are all the same. This is going to be the equation.
S²=196
14×14=196
The length of one side is 14.
