Answer:
the woman has to live 1 mile from work to minimize the expenses
Step-by-step explanation:
Given the data in the question;
the distance within 9 miles ⇒ 0 < x > 9
Total costs Q = cx + 4c/( x + 1)
costs should be minimum ⇒ dQ/dx = 0
⇒ d/dx [ cx + 4c/( x + 1) ] = 0
⇒ ( x + 1)² = 4
take square root of both side
√[ ( x + 1)² ] = √4
x + 1 = 2
x = 2 - 1
x = 1
Therefore, the woman has to live 1 mile from work to minimize the expenses
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
Answer:
The answer is $12
Step-by-step explanation:
Multiply each price by 20% (0r .2) then add them. OR
Add each price then multiply them by 20$ (or .2)
Hoped this helped!
Answer:
15
Step-by-step explanation:
