Determine which is greater, the length of a square whose area is 36 in squared or the height of a cube whose volume is 125 in cu
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Consult the attached diagram.
In the larger triangle,
tan(16°) = (7250 ft) / (<em>x</em> + <em>y</em>)
and in the smaller triangle,
tan(26°) = (7250 ft) / <em>y</em>
You want to solve for <em>x</em>.
From the first equation (I'm ignoring units from here on, all distances are measured in ft), you have
(<em>x</em> + <em>y</em>) tan(16°) = 7250
<em>x</em> tan(16°) + <em>y</em> tan(16°) = 7250
<em>x</em> tan(16°) = 7250 - <em>y</em> tan(16°)
<em>x</em> = 7250 cot(16°) - <em>y</em>
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From the second equation,
<em>y</em> = 7250 cot(26°)
Solving for <em>x</em> gives
<em>x</em> = 7250 cot(16°) - 7250 cot(26°)
<em>x</em> = 7250 (cot(16°) - cot(26°))
<em>x</em> ≈ 10,433 ft
<h3>x = 21/5</h3>
Step-by-step explanation:
<h3>___________________________</h3><h3>Given →</h3>5x:9 = 7:3
<h3>So,</h3>→ 5x/9 = 7/3
→ x = (7 × 9)/(3 × 5)
→ x = 21/5
<h3>___________________________</h3><h3>Hope it helps you!!</h3>