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andreyandreev [35.5K]
3 years ago
6

Simplify: –3(x – 5) – 8(y + 2) + (–3)(6 – 4b)

Mathematics
2 answers:
Paha777 [63]3 years ago
3 0
-3 (x - 5) - 8 (y + 2) + (-3) (6 - 4b)

First, simplify your brackets. / Your problem should look like: -3 (x - 5) - 8 (y + 2) + -3 (6 - 4b)
Second, simplify. / Your problem should look like: -3 (x - 5) - 8 (y + 2) - 3 (b - 4b)
Third, expand your problem. / Your problem should look like: -3x + 15 - 8y - 16 - 18 + 12b
Fourth, simplify. / Your problem should look like: -3x - 8y + 12b - 19

Answer: -3x - 8y + 12b - 19 (D)

Trava [24]3 years ago
3 0
−3(x−5)−8(y+2)−3(6−4b)

Distribute:

=(−3)(x)+(−3)(−5)+(−8)(y)+(−8)(2)+(−3)(6)+(−3)(−4b)

=−3x+15+−8y+−16+−18+12b

Combine Like Terms:

=−3x+15+−8y+−16+−18+12b

=(12b)+(−3x)+(−8y)+(15+−16+−18)

=12b+−3x+−8y+−19


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Hello, precalc, need help on finding csc
Ainat [17]

Recall the double angle identity for cosine:

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It follows that

\sin^2(x) = \dfrac{1 - \cos(2x)}2 \implies \sin(x) = \pm \sqrt{\dfrac{1-\cos(2x)}2} \implies \csc(x) = \pm \sqrt{\dfrac2{1-\cos(2x)}}

Since 0° < 22° < 90°, we know that sin(22°) must be positive, so csc(22°) is also positive. Let x = 22°; then the closest answer would be C,

\csc(22^\circ) = \sqrt{\dfrac2{1-\cos(44^\circ)}} = \sqrt{\dfrac2{1-\frac5{13}}} = \dfrac{\sqrt{13}}2

but the problem is that none of these claims are true; cot(32°) ≠ 4/3, cos(44°) ≠ 5/13, and csc(22°) ≠ √13/2...

3 0
2 years ago
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is it 42 or 4 and 2 separate

6 0
3 years ago
LaTanya leaves her house at 12:30pm and bikes at 12 mi/h to marta’s House she stays at marta’s House for 90mij both girls walk b
babymother [125]

Answer:

2.9 mi

Step-by-step explanation:

The time difference t between 12.30pm and 3.30pm is 3h.

Let the distance to Marat's house be s.

The equation to calculate velocity v is given by:

v = distance / time.

Now you can write an equation for the time difference t and use the two velocities and the 90 min(= 1.5h) she stays:

3 = s/12 + 1.5 + s/2.3

Solve this equation for s:

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3 years ago
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8 0
3 years ago
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bonufazy [111]

The factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

<h3>What is a factor?</h3>

A factor of n is a number which when multiplied by another number gives us the number n.

In order to factorize the polynomial 6x³ – 12x² + 7x – 14, we need to take the common terms out of the given polynomial, therefore, the polynomial can be factorized as,

6x^3-12x^2+7x - 14 \\\\

Taking the common term 6x² out from the first two terms, and then 7 from the next two terms, therefore, the polynomial can be written as

6x^3-12x^2+7x - 14 \\\\= 6x^2(x-2)+7(x-2)\\\\=(6x^2 +7)(x-2)

Hence, the factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

Learn more about Factors:

brainly.com/question/6810544

8 0
2 years ago
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