15 is the factor
15 - 1 , 3, 5 , 15
45 - 1 , 3, 5, 9, 15, 45
90 - 1, 3, 5, 6, 9, 10, 15, 30, 90
<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
Answer:
A 1:6
Step-by-step explanation:
3:18 simply to 1:6
Answer:
We can now write this is a function of time in years leading to
f
(
x
)
=
200
(
.94
)
x
f
(
5
)
≈
147
Explanation:
Firs you should consider that if its exponential then it has some form similar to
3
x
. Where we have some known part (3) and the unknown part (
x
) that we are trying to find out. Mathematically we can say it has the form
a
x
. In this case we know what the
a
is and that is the entire population that was given to us. We know over time it will change but why are we even using the exponential model.
Well it turns out that if you multiply some value over and over again it has this form. Example we multiply
2
⋅
2
⋅
2
⋅
2
=
2
4
. So if something doubled over time then this is what would happen.
Now the problem is that it will continue to decrease at the same rate leading to
a
⋅
(
.94
)
because only
94
%
of the population remains each year. After two years
a
⋅
(
.94
)
⋅
(
.94
)
. We can now write this is a function of time in years leading to
f
(
x
)
=
200
⋅
(
.94
)
x
f
(
5
)
≈
147
Step-by-step explanation:
