Answer:
(b) (c) (a)
Step-by-step explanation:
Standard Normal distribution has a higher peak in the center, with more area in this región, hence it has less area in its tails.
Student's t-Distribution has a shape similar to the Standard Normal Distribution, with the difference that the shape depends on the degree of freedom. When the degree of freedom is smaller the distribution becomes flatter, so it has more area in its tails.
Student's t-Distributionwith 1515 degrees of freedom has mores area in the tails than the Student's t-Distribution with 2020 degrees of freedom and the latter has more area than Standard Normal Distribution
Answer:
72°
Step-by-step explanation:
From the question,
Area of the circle = πr²
A = πr²................. Equation 1
Where r = radius of the circle.
⇒ r = √(A/π)............. Equation 2
Given: A = 346.5 cm², π = 3.14
r = √(346.5/3.14)
r = √(110.35)
r = 10.5 cm.
Therefore,
circumference of the circle = 2πr = 2×3.14×10.5
circumference = 65.94 m
If the length of the arc(s) is 1/5 of its circumference.
Therefore, length of arc (s) = 13.188
⇒ length of arc/circumference = 13.188/65.94 = 1/5
s/2πr = θ/360
Where θ = angle substends at the center of the circle
1/5 = θ/360
θ = 360/5
θ = 72°
Answer:
Adult=58
Step-by-step explanation:
c=child, a=adult
6.4c+9.7a=1145 equation 1
c+a=149 equation 2
a=149-c modified equation 2 to isolate a
6.4c+9.7(149-c)=1145 substitute value of a from equation 1 into equation 2
6.4c+1445.3-9.7c=1145
-3.3c=-300.3
c=91
solve for a
c+a=149
91+a=149
a=58
Check answer:
6.4c+9.7a=1145
6.4(91)+9.7(58)=1145
582.40+562.60=1145
1145=1145
A:40%
If you put 60 over 150 and x(percent of students) over 100 and cross multiply 100 and 60, you will get 6000. You then divide that by 150 which leaves you with 40 as x and 40 over 100 is 40%.
Your answer will be (B) simply use military time and subtract them and you'll get your answer best of luck.
