Let O be the point of intersection of diagonals.
Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.
In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6
Is there a picture that goes along with this question.
Answer:
D.
Step-by-step explanation:
Lines EG and CD are cut by transversal CF.
By construction, ∠FEG=∠FCD. These two angles are corresponding angles.
Since two corresponding angles are congruent, then lines EG and CD are parallel (by converse of the corresponding angles postulate).
Converse of the Corresponding Angles Postulate: If the corresponding angles formed by two lines and a transversal are congruent, then lines are parallel.
70 laps in 40 hours
1/2+1/2=4
35+35=70
I think
Answer:
21
Step-by-step explanation
3 Units x 7 Units = 21 Square Units
