Solve for x. 2 6 — = — x 2

Mathematics

1 answer:

Yuliya22 [10]3 years ago

8 0

Answer:

$\large\boxed{x=\dfrac{2}{3}}$

Step-by-step explanation:

$\dfrac{2}{x}=\dfrac{6:2}{2:2}\\\\\dfrac{2}{x}=\dfrac{3}{1}\qquad\text{cross multiply}\\\\3x=2\qquad\text{divide both sides by 3}\\\\x=\dfrac{2}{3}$

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Pls answer this i need help

Vitek1552 [10]

Step-by-step explanation:

your don't see what went wrong ?

Tyrell worked on

16 - 2(4 + 3x)

what do brackets mean ? they mean that this operation has to be done before everything else in the expression.

as this contains a variable, we cannot fully calculate it, true, but we need to keep this in mind and always treat the content of the brackets as one package.

so, whatever I do from the outside with one part of that package, I have to do also with all the other parts of that package.

so, the multiplication with -2 has to happen with both : 4 and 3x. not just with 4.

therefore, the correct simplification looks like

16 - 8 - 6x

8 - 6x or -6x + 8

Amelia multiplied correctly, but then made a mistake summing things up

10x - 3(4x + 1)

10x - 12x - 3

10x - 12x = -2x

I can't mix the pure constant -3 into the factors of x. that would be like the famous mixing of apples and oranges.

so, the result is

-2x - 3

6 0

3 years ago

Haryati had 1250 oranges.

Blababa [14]

First you subtract 242 from 1250 which gives you 1080. Then you divide it by 8 which gives you 126. Multiply this value by 3 and this shows that Haryati received $378. Hope this is helpful.

7 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$