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3 years ago

The area of the circular base of a cylinder is 36 Square units. The height of the cylinder is 2 units

Mathematics

1 answer:

coldgirl [10]3 years ago

8 0

Answer:

We are asked to solve for the lateral area of the cylinder and the formula is shown below:

Lateral area = 2*pi*r*h

We are also given with the area of the base such as:

Area of the base = 36pi square units

Area of the base = pi*r²

Solving for radius:

36pi = pi*r²

r=6 inches

Solving for the lateral area when height is 2 units:

Lateral area = 2*pi*6*2

Lateral area = 24pi inches²

The answer is the letter "B" 24 square units

Step-by-step explanation:

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Whats the value of x? 2−(3x−4)=2x−9

coldgirl [10]

Answer:

x=3

Step-by-step explanation:

Use pemdas!

First use distributive property to get rid of the parenthesis, by multiplying 2 by 3x and -4. Then combine like terms and use inverse operations to simplify each side until you get it down to just x! Hope this helped! :)

3 0

3 years ago

Given P(E)= 0.24 and P(FnE)= 0.17, find P(F| E). Round the answer to the nearest hundredth. A. 029 B. 0.40 C. 0.71 D. 1.41

romanna [79]

Given P(E) = 0.24 and P(F ∩ E) = 0.17

It says to find conditional probability of F given E has occurred.

We know the formula of conditional probability is given by :-

P(F ║ E) = $\frac{P(E\;and\; F)}{P(E)}$

P(F ║ E) = $\frac{0.17}{0.24}$ = 0.708333

P(F ║ E) = 0.71

Hence, option C i.e. 0.71 is the final answer.

7 0

3 years ago

Help plz Help Help Help

jek_recluse [69]

The answer is -45 so C.

5 0

3 years ago

Read 2 more answers

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

SOLUTION:

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

8 0

3 years ago

The length around the outside of semicircle O from point L through point M to point N is 14 centimeters. The perimeter of semici

Luden [163]

The area would be 83.67 cm.

A semicircle is half of a circle. The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle. The formula for circumference is:

C=πd

Using our information, we have

22.92 = 0.5(3.14)d
22.92 = 1.57d

Divide both sides by 1.57:

22.92/1.57 = 1.57d/1.57
14.6≈d

Since the diameter is 14.6, the radius is 14.6/2 = 7.3.

We use the radius for the area of the semicircle:

A=0.5πr²
=0.5(3.14)(7.3)²
=83.67

3 0

3 years ago